【发布时间】：2015-02-24 04:30:22
【问题描述】：
我是 python/django 的新手，我想知道：在 Django 中使用视图中的表单过滤结果的最佳方法是什么？
我需要根据 CandidateLook 模型按发色过滤候选人，根据 CandidateToJob 模型按状态过滤候选人。
但我收到一个错误：forms.py 中的语法无效： if self.cleaned_data['status']:
如果我删除这一行，forms.py 中的语法仍然无效： 返回job_candidates
提前致谢。
这是我的代码：
#models.py
class Job(models.Model):
candidate = models.ManyToManyField('Candidate', through='CandidateToJob')
title = models.CharField(max_length=500)
...
class Candidate(models.Model):
user = models.OneToOneField(User, primary_key=True)
photo = models.ImageField(upload_to=user_profile_path)
class CandidateLook(models.Model):
user = models.OneToOneField(User, primary_key=True)
HAIRCOLOR_CHOICES = (
('1', 'Black'),
('2', 'Brown'),
('3', 'Blonde'),
('4', 'Red')
)
haircolor = models.CharField(max_length=2, choices=HAIRCOLOR_CHOICES)
class CandidateToJob(models.Model):
job = models.ForeignKey(Job, related_name='applied_to')
candidate = models.ForeignKey(Candidate, related_name='from_user')
STATUS_CHOICES = (
('0', 'New'),
('1', 'Not approved'),
('2', 'Approved')
)
status = models.CharField(max_length=2, choices=STATUS_CHOICES)
这是我的看法：
#views.py
class Screening(generic.DetailView):
model = Job
template_name = 'dashboard/screening.html'
def get_context_data(self, **kwargs):
context = super(Screening, self).get_context_data(**kwargs)
# Fetch the sender_id for each unread message.
# Count the number of times that the sender_id was included.
# Then convert the list of tuples into a dictionary for quick lookup.
sent_messages = dict(
self.request.user.received_messages.filter(
read_at__isnull=True
).values('sender_id').annotate(
messages_sent=Count('sender_id')
).values_list('sender_id', 'messages_sent')
)
form_cand = ScreeningForm(self.request.GET)
if form_cand.is_valid():
job_candidates = form_cand.filter_job_candidates(self.object)
else:
job_candidates = self.object.applied_to.all().order_by('candidate')
candidates = []
for candidate in self.object.applied_to.all().order_by('candidate'):
candidate.messages_sent = sent_messages.get(candidate.candidate.user.id)
candidates.append(candidate)
context['candidate_list'] = candidates
context['form_cand'] = form_cand
return context
表格
#forms.py
class StatusForm(ModelForm):
STATUS_CHOICES = (
('0', 'New'),
('1', 'Not approved'),
('2', 'Approved')
)
status = forms.ChoiceField(required=False, widget=forms.RadioSelect(attrs={'class': ''}), choices=STATUS_CHOICES)
class Meta:
model = CandidateToJob
exclude = ['candidate', 'job']
class HairColorForm(ModelForm):
HAIRCOLOR_CHOICES = (
('1', 'Black'),
('2', 'Brown'),
('3', 'Blonde'),
('4', 'Red')
)
status = forms.ChoiceField(required=False, widget=forms.RadioSelect(attrs={'class': ''}), choices=HAIRCOLOR_CHOICES)
class Meta:
model = CandidateLook
class ScreeningForm(forms.Form):
haircolor = forms.ChoiceField(choices=CandidateLook.HAIRCOLOR_CHOICES, required=False)
status = forms.ChoiceField(choices=CandidateToJob.STATUS_CHOICES, required=False)
def filter_job_candidates(job):
assert self.is_valid()
job_candidates = job.applied_to.all().order_by('candidate')
if self.cleaned_data['haircolor']:
job_candidates = job_candidates.filter(candidate__candidatelook__haircolor=self.cleaned_data['haircolor']
if self.cleaned_data['status']:
job_candidates = job_candidates.filter(status=self.cleaned_data['status']
return job_candidates
还有模板：
#html
{{ job.title }}
{% for candidate in candidate_list %}
{{ candidate }}
{% for status in candidate.status %}
{{ candidate.get_status_display }}
{% endfor %}
{% endfor %}
【问题讨论】：
-
看看
django-filterdjango-filter.readthedocs.org/en/latest -
嗨，andi，我已经尝试过 django-filter 和 django-datafilters，但不幸的是我无法实现我所需要的。我刚刚更新了我的帖子，因为我忘了展示我的表格。
标签： python django forms filter