按时间序列完成时间频率表[重复]

【问题标题】：Complete a table of time-frequency by time series [duplicate]按时间序列完成时间频率表[重复]
【发布时间】：2018-02-23 07:06:37
【问题描述】：

考虑一个时间频率表

2008-01-01 2008-01-03 2008-01-05 2008-01-06 2008-01-07 2008-01-08
         1          8          2          2          3          1

请注意，2008-01-02 和 2008-01-04 已丢失。

预期的结果如下所示：

2008-01-01 2008-01-02 2008-01-03 2008-01-04 2008-01-05 2008-01-06 2008-01-07 2008-01-08
         1          0          8          0          2          2          3          1

或者以日期框的形式：

   Time    Frequency
2008-01-01    1
2008-01-02    0
2008-01-03    8
2008-01-04    0
2008-01-05    2
2008-01-06    2
2008-01-07    3
2008-01-08    1

【问题讨论】：

标签： r time-series

【解决方案1】：

更好的选择是转换为factor 并指定levels，然后执行table

rndates <- range(dates)
table(factor(dates, levels = as.character(seq(rndates[1], rndates[2], by = "1 day"))))
#  2008-01-01 2008-01-02 2008-01-03 2008-01-04 2008-01-05 2008-01-06 2008-01-07 2008-01-08 
#        4          0          7          0          1          5          6          2

数据

set.seed(24)
dates <- sample(as.Date(c("2008-01-01", "2008-01-03", "2008-01-05", 
    "2008-01-06", "2008-01-07", "2008-01-08")), 25, replace = TRUE)

【讨论】：