根据另一个对象值过滤数组[重复]

Question

我想过滤这个程序数组（我已经简化了对象）：

const programs = [
      {
        format: "In-Person",
        schedule: "Full-Time",
      },
      {
        format: "Remote",
        schedule: "Full-Time",
      },
      {
        format: "In-Person",
        schedule: "Part-Time",
      },
      {
        format: "Remote",
        schedule: "Part-Time",
      }
    ]

基于过滤器对象：

const filters = {format: "Remote", schedule:"Full-Time"}

我的尝试：

  let filteredPrograms = programs.filter((program) => {
    return Object.entries(filters).every(([key, value]) => {
      program[key] == value;
    });
  });

这应该分析每个程序，并且允许是通过过滤器IF： 对于每个过滤器键，程序[过滤器键]值与过滤器值匹配

但是我得到了一个用于过滤程序的空数组

Answer 1

在every回调中返回比较结果：

const programs=[{format:"In-Person",schedule:"Full-Time"},{format:"Remote",schedule:"Full-Time"},{format:"In-Person",schedule:"Part-Time"},{format:"Remote",schedule:"Part-Time"}],filters={format:"Remote",schedule:"Full-Time"};

let filteredPrograms = programs.filter((program) => {
  return Object.entries(filters).every(([key, value]) => {
    return program[key] == value;
  });
});
console.log(filteredPrograms)

或者把它变成一个箭头函数：

const programs=[{format:"In-Person",schedule:"Full-Time"},{format:"Remote",schedule:"Full-Time"},{format:"In-Person",schedule:"Part-Time"},{format:"Remote",schedule:"Part-Time"}],filters={format:"Remote",schedule:"Full-Time"};

let filteredPrograms = programs.filter((program) => {
  return Object.entries(filters).every(([key, value]) => program[key] == value);
});
console.log(filteredPrograms)