【发布时间】:2021-04-27 11:09:35
【问题描述】:
我有一个@Async 方法,我试图在其中添加@Retry,但是当发生异常时永远不会执行回退方法。我也在尝试测试这种抛出异常的模拟,但由于它永远不会进入回退方法,所以它永远不会成功。
这是我的代码:
@Retry(name = "insertarOperacionPendienteService", fallbackMethod = "fallbackInsertarOperacionPendiente")
@Override
@Async
public CompletableFuture<String> insertarOperacionPendiente(final OperacionPendienteWeb operacionPendienteWeb) throws InterruptedException, ExecutionException {
StringBuilder debugMessage = new StringBuilder("[insertarOperacionPendiente] Operacion pendiente a insertar en BB.DD.: ").append(operacionPendienteWeb);
CompletableFuture<String> result = new CompletableFuture<>();
HttpEntity<List<OperacionPendienteWeb>> entity = new HttpEntity<>();
UriComponentsBuilder builder = UriComponentsBuilder.fromHttpUrl("url");
try {
rest.exchange(builder.toUriString(), HttpMethod.POST, entity, Void.class);
} catch (HttpClientErrorException | HttpServerErrorException e) {
result.completeExceptionally(e);
} catch (Exception e) {
result.completeExceptionally(e);
}
result.complete("OK");
return result;
}
public CompletableFuture<String> fallbackInsertarOperacionPendiente(Exception e) {
System.out.println("HI");
throw new InternalServerErrorDarwinException("Error al insertar la operacion pendiente.");
}
测试:
@Test(expected = InternalServerErrorDarwinException.class)
public void procesarOperacionPendienteKO1() throws InterruptedException, ExecutionException, ParseException {
when(rest.exchange(Mockito.anyString(),
Mockito.any(HttpMethod.class),
Mockito.any(HttpEntity.class),
Mockito.eq(Void.class)))
.thenThrow(new NullPointerException());
this.operacionesPendientesService.insertarOperacionPendiente(obtenerOperacionPendienteWeb()).get();
verify(rest, timeout(100).times(1)).exchange(Mockito.anyString(),
Mockito.any(HttpMethod.class),
Mockito.any(HttpEntity.class),
Mockito.eq(Void.class));
}
我错过了什么吗?
谢谢!
【问题讨论】:
-
我首先注意到的一件事是您捕获了所有异常。所以不会有重试恕我直言
-
result.completeExceptionally(e);就像一个“扔”。如果我改用“throw”,它也不起作用,如果我把方法重新同步,它就起作用了
标签: spring-boot junit mockito resilience4j resilience4j-retry