如何编写正确的 JUnit 测试用例休息控制器答案

【问题标题】：How to write proper JUnit test case rest controllers如何编写正确的 JUnit 测试用例休息控制器
【发布时间】：2019-12-16 11:44:30
【问题描述】：

我想使用 mockito 框架编写 JUnit 测试用例休息控制器。我想知道如何为 get 和 post 之类的 http 请求编写测试用例。还有如何测试上传文档的api。

【问题讨论】：

标签： junit mockito

【解决方案1】：

import static org.mockito.ArgumentMatchers.any;
import static org.mockito.ArgumentMatchers.anyBoolean;
import static org.mockito.ArgumentMatchers.anyString;
import static org.mockito.Mockito.doNothing;
import static org.mockito.Mockito.when;
import static org.springframework.test.web.servlet.request.MockMvcRequestBuilders.fileUpload;
import static org.springframework.test.web.servlet.request.MockMvcRequestBuilders.get;
import static org.springframework.test.web.servlet.request.MockMvcRequestBuilders.post;

@RunWith(MockitoJUnitRunner.class)
@WebMvcTest
@AutoConfigureMockMvc
public class ControllerTest {
    @Autowired
    private MockMvc mvc;

    @Mock
    Service service;

    @InjectMocks
    private Controller controller;

    @Before
    public void setup() {
        MockitoAnnotations.initMocks(this);
        mvc = MockMvcBuilders.standaloneSetup(marketplaceCatalogController)
               .setCustomArgumentResolvers(new PageableHandlerMethodArgumentResolver())
               .setViewResolvers(new ViewResolver() {
                   @Override
                   public View resolveViewName(String viewName, Locale locale) throws Exception {
                      return new MappingJackson2JsonView();
                  }
               }).build();
    }

    @Test
    public void testGetMethod() throws Exception {        
        when(service.getMethod(Mockito.any(SomeClass.class))).thenReturn(new SomeOtherClass);   
        doNothing().when(service).someMethod();     
        mvc.perform(get("/get-method").param("paramKey", 
                                "paramValue")).andExpect(status().isOk()).andDo(print());
    }

    @Test
    public void testStatusTnC() throws Exception {
        String payload = "{\"key1\": \"value1\", \"key2\": \"value2\"}";
        mvc.perform(post("/post-method").content(payload)).andExpect(status().isOk()).andDo(print());
    }

    @Test
    public void testUploadFile() throws Exception {
        when(service.uploadSomeContent(any(), any(), anyString(), anyString())).thenReturn(new SomeClass());        
        mvc.perform(fileUpload("/post-request/uploadFile").file("somefile", "Hello, World!".getBytes()).param("param1", "value1").contentType(MediaType.MULTIPART_FORM_DATA)).andExpect(status().isOk()).andDo(print());
    }
}

【讨论】：