json输出转换为php字符串答案

【问题标题】：json output convert to php stringjson输出转换为php字符串
【发布时间】：2015-07-18 15:46:27
【问题描述】：

下面是我的工作 api，但 "echo $data" 的结果只有 "array" 和 "echo $data["data"]["operatorid"]" 没有什么屏幕会变黑。那么如何将json reponse 转换为php 字符串并从中获取特定值

$opts = array(
'http'=>array(
'method'=>"GET",
'header'=>"X-Mashape-Key: XXXXXXXX"               
)
);

$context = stream_context_create($opts);
$res = file_get_contents('https://tariff-plan-api-datayuge.p.mashape.com/index.php?circleid=kerala&limit=50&operatorid=BSNL&recharge_type=top', false, $context);
$data = (json_decode($res, true));
echo $data["data"]["operatorid"];

json 响应：

{
"data": [
{
  "id": "3148",
  "operatorid": "BSNL",
  "circleid": "Kerala",
  "recharge_amount": "150",
  "recharge_talktime": "150",
  "recharge_validity": "Unlimited",
  "recharge_shortdesc": "Recharge Of Rs 150 By BSNL",
  "recharge_longdesc": "Full Talktime (offer valid upto 23 Mar 2015)",
  "recharge_type": "Full Talktime"
},
{
  "id": "3149",
  "operatorid": "BSNL",
  "circleid": "Kerala",
  "recharge_amount": "250",
  "recharge_talktime": "250",
  "recharge_validity": "Unlimited",
  "recharge_shortdesc": "Recharge Of Rs 250 By BSNL",
  "recharge_longdesc": "Full Talktime (offer valid upto 23 Mar 2015)",
  "recharge_type": "Full Talktime"
},
{
  "id": "3150",
  "operatorid": "BSNL",
  "circleid": "Kerala",
  "recharge_amount": "550",
  "recharge_talktime": "550",
  "recharge_validity": "Unlimited",
  "recharge_shortdesc": "Recharge Of Rs 550 By BSNL",
  "recharge_longdesc": "Full Talktime (offer valid upto 23 Mar 2015)",
  "recharge_type": "Full Talktime"
},
{
  "id": "3151",
  "operatorid": "BSNL",
  "circleid": "Kerala",
  "recharge_amount": "1000",
  "recharge_talktime": "1100",
  "recharge_validity": "Unlimited",
  "recharge_shortdesc": "Recharge Of Rs 1000 By BSNL",
  "recharge_longdesc": "Extra Talktime (offer is valid till 23 Mar 2015)",
  "recharge_type": "Full Talktime"
},
{
  "id": "3152",
  "operatorid": "BSNL",
  "circleid": "Kerala",
  "recharge_amount": "1100",
  "recharge_talktime": "1210",
  "recharge_validity": "Unlimited",
  "recharge_shortdesc": "Recharge Of Rs 1100 By BSNL",
  "recharge_longdesc": "Extra Talktime (offer is valid till 23 Mar 2015)",
  "recharge_type": "Full Talktime"
},
{
  "id": "3153",
  "operatorid": "BSNL",
  "circleid": "Kerala",
  "recharge_amount": "1500",
  "recharge_talktime": "1650",
  "recharge_validity": "Unlimited",
  "recharge_shortdesc": "Recharge Of Rs 1500 By BSNL",
  "recharge_longdesc": "Extra Talktime (offer is valid till 23 Mar 2015)",
  "recharge_type": "Full Talktime"
},
{
  "id": "3154",
  "operatorid": "BSNL",
  "circleid": "Kerala",
  "recharge_amount": "2000",
  "recharge_talktime": "2200",
  "recharge_validity": "Unlimited",
  "recharge_shortdesc": "Recharge Of Rs 2000 By BSNL",
  "recharge_longdesc": "Extra Talktime (offer is valid till 23 Mar 2015)",
  "recharge_type": "Full Talktime"
}
]

【问题讨论】：

echo $data["data"][0]["operatorid"] 输出什么？您在“数据”中有多个数组，因此您需要引用其中之一。
echo $data["data"][0]["operatorid"];
感谢@maxxi 和 splash58

标签： php json mashup

【解决方案1】：

该 JSON 字符串转换为一个 PHP 对象，该对象具有一个名为 data 的属性，它是一个对象数组

来自print_r()的输出

所以要引用单个项目，您需要使用此语法

$context = stream_context_create($opts);
$res = file_get_contents('https://tariff-plan-api-datayuge.p.mashape.com/index.php?circleid=kerala&limit=50&operatorid=BSNL&recharge_type=top', false, $context);

$data = (json_decode($res));
echo $data->data[0]->operatorid;

如果使用$data以外的变量名可能会更容易理解所以

$jsonObj = (json_decode($res));
echo $jsonObj -> data[0] -> operatorid;

或者，如果您正在处理所有事件

$jsonObj = (json_decode($res));
foreach ($jsonObj -> data as $data) {
    echo $data -> operatorid;
}

【讨论】：

【解决方案2】：

$data 拥有一个多维数组 - “数据”，它本身拥有多个数组。

echo $data["data"]["operatorid"] 不会返回任何内容，因为您没有指定要从哪些数组中打印operatorid。

使用以下内容指定您要定位的数组

$data["data"][*index*]["operatorid"]

或者像这样遍历你的 $data 数组

foreach( $data as $Adata ){
    foreach( $Adata as $arr ){
        echo $arr['operatorid'];
    }
}

【讨论】：