【发布时间】:2017-06-23 14:55:35
【问题描述】:
我正在使用 Spring Data JPA,并且为了生成动态查询,我使用 Spring Data JPA 规范。它适用于类型 Date 旁边。我收到以下异常:
Parameter value [2017-06-01] did not match expected type [java.time.LocalDate (n/a)]; nested exception is java.lang.IllegalArgumentException: Parameter value [2017-06-01] did not match expected type [java.time.LocalDate (n/a)]]
但是我传入的参数值是 java.util.Date 类型。可能是什么原因?
这是我的实体:
private String name;
@Column(name = "user_id")
private Long userId;
@Column(name = "version_id")
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
private Long versionId;
@Column(name = "created_date")
private LocalDate createdDate;
这里是
public ViewDetailSpecificationsBuilder createSearchSpecifications(ViewSearch view) {
ViewDetailSpecificationsBuilder builder = new ViewDetailSpecificationsBuilder();
if (StringUtils.isNotBlank(view.getName())) {
builder.with("name", Operation.DEFAULT, view.getName());
}
if (view.getStartDate() != null) {
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
LocalDate date = LocalDate.parse(view.getStartDate(), formatter);
builder.with("createdDate", Operation.GREATHERTHANEQUALTO, date);
}
if (view.getVersion() != null) {
builder.with("version", Operation.DEFAULT, view.getVersion());
}
return builder;
}
这会引发以下异常:
org.springframework.dao.InvalidDataAccessApiUsageException: Parameter value [Thu%Jun%01%00:00:00%AMT%2017] did not match expected type [java.util.Date (n/a)]; nested exception is java.lang.IllegalArgumentException: Parameter value [Thu%Jun%01%00:00:00%AMT%2017] did not match expected type [java.util.Date (n/a)]
如果我格式化 startDate (formatter.format(startDate)) 它会抛出上述异常。
【问题讨论】:
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标签: postgresql spring-data-jpa