【发布时间】:2016-09-30 15:07:01
【问题描述】:
同学们,我有两张桌子,选择获取CHAIN:
SELECT OD_CHAINS_REQ.CHAIN
FROM OD_CHAINS_REQ
JOIN od_face_accs
ON od_face_accs.ID = OD_CHAINS_REQ.ACCOUNT
WHERE od_face_accs.ACNT='1608290029'
ORDER BY OD_CHAINS_REQ.NUM;
OD_CHAINS_REQtable 中的记录少于 10 条,od_face_accstable 中的记录超过 1000 条。
我正在尝试通过 JPA 执行此选择。但是,据我了解,我需要创建实体OdChainsReqEntity:
@Entity
@Table(name = "OD_CHAINS_REQ", schema = "", catalog = "")
@IdClass(OdChainsReqEntityPK.class)
public class OdChainsReqEntity {
private Integer chain;
private Integer num;
private Integer account;
@Id
@Column(name = "CHAIN")
public Integer getChain() {
return chain;
}
public void setChain(Integer chain) {
this.chain = chain;
}
@Basic
@Column(name = "NUM")
public Integer getNum() {
return num;
}
public void setNum(Integer num) {
this.num = num;
}
@Id
@Column(name = "ACCOUNT")
public Integer getAccount() {
return account;
}
public void setAccount(Integer account) {
this.account = account;
}
@OneToOne
@JoinColumn(name = "ACCOUNT", referencedColumnName = "ID")
private OdFaceAccsEntity odFaceAccsEntity;
public OdFaceAccsEntity getOdFaceAccsEntity() {
return odFaceAccsEntity;
}
public void setOdFaceAccsEntity(OdFaceAccsEntity odFaceAccsEntity) {
this.odFaceAccsEntity = odFaceAccsEntity;
}
/*@Overrides*/*/
}
和OdFaceAccsEntity实体:
@Entity
@Table(name = "OD_FACE_ACCS", schema = "", catalog = "")
public class OdFaceAccsEntity {
private Integer id;
private String acnt;
@Id
@Column(name = "ID")
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
@Basic
@Column(name = "ACNT")
public String getAcnt() {
return acnt;
}
public void setAcnt(String acnt) {
this.acnt = acnt;
}
/*@Overrides*/
@OneToOne
@JoinColumn (referencedColumnName = "ACCOUNT")
private OdChainsReqEntity odChainsReqEntity;
public OdChainsReqEntity getOdChainsReqEntity() {
return odChainsReqEntity;
}
public void setOdChainsReqEntity(OdChainsReqEntity odChainsReqEntity) {
this.odChainsReqEntity = odChainsReqEntity;
}
}
所以我正在尝试使用测试来获取链
@Test
public void getChainByDepoAcc() throws Exception {
OdFaceAccsEntity odFaceAccsEntity = new OdFaceAccsEntity();
odFaceAccsEntity.setAcnt("1608290029");
List<OdFaceAccsEntity> odFaceAccsEntities = odFaceAccsDAO.getAcc(odFaceAccsEntity);
for (int i = 0; i < odFaceAccsEntities.size(); i++) {
LOG.info(odFaceAccsEntities.get(i).getId());
LOG.info(odFaceAccsEntities.get(i).getOdChainsReqEntity().getChain());
}
}
但它返回异常:
原因:org.hibernate.MappingException:无法确定类型 对于:com.alcap.app.JPA.Entities.OdFaceAccsEntity,在表中: OD_CHAINS_REQ,对于列: [org.hibernate.mapping.Column(odFaceAccsEntity)]
如何正确指定实体中的关联以避免异常?
更新 我尝试过的最后一个 DAO 实现:
@Transactional(value = "txMan", readOnly = true)
public List <OdChainsReqEntity> getOdChainsReqByDEPOAcc(String in$depoAccnt) {
Query query = em.createQuery("SELECT cre FROM OdChainsReqEntity cre " +
"join OdFaceAccsEntity fae on fae.id = cre.account "+
"where fae.acnt = :depoAcc");
query.setParameter("depoAcc", in$depoAccnt);
List<OdChainsReqEntity> result = query.getResultList();
return result;
}
我也试过这个(但我不知道它是否适合join选择):
public List<OdChainsReqEntity> getOdChainsReqByAnyParam(OdChainsReqEntity odChainsReqEntity) {
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<OdChainsReqEntity> criteriaQuery = cb.createQuery(OdChainsReqEntity.class);
Root<OdChainsReqEntity> entityRoot = criteriaQuery.from(OdChainsReqEntity.class);
Predicate criteria = cb.conjunction();
if (odChainsReqEntity.getChain() != null) {Predicate p = cb.equal(entityRoot.get("chain"), odChainsReqEntity.getChain()); criteria = cb.and(criteria, p);}
if (odChainsReqEntity.getNum() != null) {Predicate p = cb.equal(entityRoot.get("num"), odChainsReqEntity.getNum()); criteria = cb.and(criteria, p);}
if (odChainsReqEntity.getAccount() != null) {Predicate p = cb.equal(entityRoot.get("account"), odChainsReqEntity.getAccount()); criteria = cb.and(criteria, p);}
criteriaQuery.where(criteria);
List<OdChainsReqEntity> result = em.createQuery(criteriaQuery).getResultList();
return result;
}
【问题讨论】:
标签: java hibernate jpa annotations