试图区分两个2变量Java

Question

我试图显示两支选定球队之间获胜和平局的百分比，但我发现很难区分任何一支球队。

Connection con = DBConnector.connect();
             ResultSet rs = con.createStatement().executeQuery("SELECT DISTINCT t1.title AS title1, t2.title AS title2, g.score1, g.score2, g.winner AS winner, g.team1_id AS team1,  g.home AS home FROM games g INNER JOIN teams AS t1 ON g.team1_id = t1.id INNER JOIN teams AS t2 ON g.team2_id = t2.id WHERE (t1.title = '"+team1 +"' AND t2.title = '" +team2+ "') OR (t1.title = '"+team2 +"' AND t2.title = '" +team1+ "');");
            while(rs.next()){

                if(rs.getString("team1").equals(rs.getString("home"))){
                if(rs.getInt("winner") == 1){
                        teamOneWin++;
                    }else{
                        teamTwoWin++;
                    }

                }else if(rs.getInt("winner") == 2){
                    if(rs.getString("team1").equals(rs.getString("home"))){
                        teamOneWin++;
                    }else{
                        teamTwoWin++;
                    }

                }else if(rs.getInt("winner") == 0){
                    if(rs.getString("team1").equals(rs.getString("home"))){
                    draw++;
                    }


            }

我正在检查查询中的 team1 值是否等于查询中的主队值。如果它们相等并且团队 1 是列获胜者中的值，我希望 teamOneWin 增加。我指定获胜者 1、获胜者 2 和获胜者 0（比赛为平局）。我指定这些是因为我有一个未播放的获胜者 3 值。

我知道下面这行是有缺陷的，因为 team1 总是等于主队，但我需要一种方法来区分任何一支球队并根据获胜者的价值增加正确的球队。

if(rs.getString("team1").equals(rs.getString("home"))){

在我的 SQL 中使用 COUNT 会更好吗？

这是我的游戏桌的表格结构：

CREATE TABLE "games" (
    "team1_id"  integer NOT NULL,
    "team2_id"  integer NOT NULL,
    "home"  integer,
    "score1"    varchar DEFAULT null,
    "score2"    varchar DEFAULT null,
    "winner"    integer,
    "created_at"    DATETIME DEFAULT CURRENT_TIMESTAMP,
    PRIMARY KEY("team1_id","created_at"),
    FOREIGN KEY("team1_id") REFERENCES "teams"("id"),
    FOREIGN KEY("team2_id") REFERENCES "teams"("id")
);

这是我的团队的表结构：

CREATE TABLE "teams" (
    "id"    integer NOT NULL PRIMARY KEY AUTOINCREMENT,
    "title" varchar NOT NULL,
    "code"  varchar,
    "synonyms"  varchar,
    "address"   varchar,
    "web"   varchar,
    "created_at"    DATETIME DEFAULT CURRENT_TIMESTAMP
);

非常感谢。

Answer 1

据我了解，在games 表的winner 列中，您存储了一个整数值，表示：

0: draw
1 or 2: either team won
3: game not played 

如果是这种情况，那么我认为您无需从数据库中获取数据并遍历每一行即可获得所需的结果。
试试这个查询：

select 
  t.title1, t.title2,
  100.0 * t.draws / (t.draws + t.wins) percentdraws,
  100.0 * t.wins / (t.draws + t.wins) percentwins
from (
  select 
    'team1' title1, 'team2' title2,
    sum(case when g.winner = 0 then 1 else 0 end) draws,
    sum(case when g.winner <> 0 then 1 else 0 end) wins
  from games g 
  inner join teams t1 on t1.id = g.team1_id 
  inner join teams t2 on t2.id = g.team2_id
  where 
    ((t1.title = 'team1' and t2.title = 'team2') or (t2.title = 'team1' and t1.title = 'team2'))
    and 
    g.winner < 3
) t  

将'team1' 和'team2' 更改为所选团队的名称。