【发布时间】:2015-02-19 09:04:09
【问题描述】:
如何定义休眠条件生成SQL:
SELECT * FROM table WHERE columnA - columnB > anyInteger
? 我知道有:
Restrictions.sqlRestriction("column_a - column_b > "+int);
但它取决于列名,而不是类属性。有什么办法解决吗?
【问题讨论】:
标签: java sql hibernate criteria
如何定义休眠条件生成SQL:
SELECT * FROM table WHERE columnA - columnB > anyInteger
? 我知道有:
Restrictions.sqlRestriction("column_a - column_b > "+int);
但它取决于列名,而不是类属性。有什么办法解决吗?
【问题讨论】:
标签: java sql hibernate criteria
如果您希望能够查询列名,我认为您不能避免必须用列名来表达限制,因为计算必须发生在数据库端而不是 Java 端。但是您可以做的是将附加属性映射为 formula 以将 SQL 封装在 Hibernate 映射定义中,而不必每次查询时都重复它:
@Formula("column_a - column_b")
private int difference;
然后你会查询它
Restrictions.gt("difference", value)
【讨论】:
好的,我找到了解决方案,而不是解决方法。我必须创建 Criterion 类的新实现。这是代码:
public class DifferenceCriterion implements Criterion{
private static final long serialVersionUID = -8082375591482621375L;
private String firstProperty;
private String secondProperty;
private int value;
public DifferenceCriterion(String propertyA, String propertyB, int value) {
this.firstProperty = propertyA;
this.secondProperty = propertyB;
this.value = value;
}
@Override
public TypedValue[] getTypedValues(Criteria criteria, CriteriaQuery criteriaQuery) throws HibernateException {
TypedValue tvFirst = criteriaQuery.getTypedValue(criteria, firstProperty, value);
TypedValue tvSecond = criteriaQuery.getTypedValue(criteria, secondProperty, value);
if(!tvFirst.equals(tvSecond)){
throw new HibernateException("Properties typedValues are not the same!");
}
return new TypedValue[] {tvFirst};
}
@Override
public String toSqlString(Criteria criteria, CriteriaQuery criteriaQuery) throws HibernateException {
final String[] columnsA = criteriaQuery.getColumnsUsingProjection(criteria, this.firstProperty);
final String[] columnsB = criteriaQuery.getColumnsUsingProjection(criteria, this.secondProperty);
return columnsA[0] + " - "+columnsB[0] + " > ?";
}
}
并输入我的条件查询方法:
criteria.add(new DifferenceCriterion("columnA", "columnB", someInt));
【讨论】: