【发布时间】:2016-01-28 12:52:13
【问题描述】:
我正在使用允许从图库中选择图像并将其上传到在线网络托管服务的 php 脚本。图片上传了,但是上传的.jpg文件是空的,命名为0.jpg,大小也显示为0字节。当我尝试打开它显示的图像时
"图片http://testimage.site88.net/pic/0.jpg无法显示 因为它包含错误”
这可能是什么原因? php代码如下
<?php
$name = $_POST['name']; //image name
$image = $_POST['image']; //image in string format
//decode the image
$decodedImage = base64_decode($image);
//upload the image
file_put_contents("pic/".$name.".jpg", $decodedImage);
安卓代码是:
import android.app.Activity;
import android.content.Intent;
import android.graphics.Bitmap;
import android.graphics.drawable.BitmapDrawable;
import android.net.Uri;
import android.os.AsyncTask;
import android.os.Bundle;
import android.provider.MediaStore;
import android.util.Base64;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.ImageView;
import android.widget.Toast;
import java.io.ByteArrayOutputStream;
import java.io.UnsupportedEncodingException;
import java.net.URLEncoder;
import java.util.HashMap;
import java.util.Map;
public class MainActivity extends Activity {
//define global views variable
public ImageView imageView;
public Button selectImage,
uploadImage;
public String SERVER = "http://testimage.site88.net/saveImage.php",
timestamp;
private static final String TAG = MainActivity.class.getSimpleName();
private static final int RESULT_SELECT_IMAGE = 1;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
//instantiate view
imageView = (ImageView) findViewById(R.id.imageView);
selectImage = (Button) findViewById(R.id.selectImage);
uploadImage = (Button) findViewById(R.id.uploadImage);
//when selectImage button is pressed
selectImage.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
//call the function to select image from album
selectImage();
}
});
//when uploadImage button is pressed
uploadImage.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
//get image in bitmap format
Bitmap image = ((BitmapDrawable) imageView.getDrawable()).getBitmap();
//execute the async task and upload the image to server
new Upload(image,"IMG_"+timestamp).execute();
}
});
}
//function to select a image
private void selectImage(){
//open album to select image
Intent gallaryIntent = new Intent(Intent.ACTION_PICK,MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
startActivityForResult(gallaryIntent, RESULT_SELECT_IMAGE);
}
/*
* This function is called when we pick some image from the album
* */
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == RESULT_SELECT_IMAGE && resultCode == RESULT_OK && data != null){
//set the selected image to image variable
Uri image = data.getData();
imageView.setImageURI(image);
//get the current timeStamp and strore that in the time Variable
Long tsLong = System.currentTimeMillis() / 1000;
timestamp = tsLong.toString();
Toast.makeText(getApplicationContext(),timestamp,Toast.LENGTH_SHORT).show();
}
}
private String hashMapToUrl(HashMap<String, String> params) throws UnsupportedEncodingException {
StringBuilder result = new StringBuilder();
boolean first = true;
for(Map.Entry<String, String> entry : params.entrySet()){
if (first)
first = false;
else
result.append("&");
result.append(URLEncoder.encode(entry.getKey(), "UTF-8"));
result.append("=");
result.append(URLEncoder.encode(entry.getValue(), "UTF-8"));
}
return result.toString();
}
//async task to upload image
private class Upload extends AsyncTask<Void,Void,String>{
private Bitmap image;
private String name;
public Upload(Bitmap image,String name){
this.image = image;
this.name = name;
}
@Override
protected String doInBackground(Void... params) {
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
//compress the image to jpg format
image.compress(Bitmap.CompressFormat.JPEG,100,byteArrayOutputStream);
/*
* encode image to base64 so that it can be picked by saveImage.php file
* */
String encodeImage = Base64.encodeToString(byteArrayOutputStream.toByteArray(),Base64.DEFAULT);
//generate hashMap to store encodedImage and the name
HashMap<String,String> detail = new HashMap<>();
detail.put("name", name);
detail.put("image", encodeImage);
try{
//convert this HashMap to encodedUrl to send to php file
String dataToSend = hashMapToUrl(detail);
//make a Http request and send data to saveImage.php file
String response = Request.post(SERVER,dataToSend);
//return the response
return response;
}catch (Exception e){
e.printStackTrace();
Log.e(TAG,"ERROR "+e);
return null;
}
}
@Override
protected void onPostExecute(String s) {
//show image uploaded
Toast.makeText(getApplicationContext(),"Image Uploaded",Toast.LENGTH_SHORT).show();
}
}
}
提前致谢。
【问题讨论】:
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这是你的真实代码吗?用“[”在里面???也许修复第一个,然后再试一次,当你尝试它时查看 php 日志,并发布你在那里看到的错误,以防它不起作用。此外,您可能希望显示用于发布图像的 android 代码,因为它看起来并不简单,因为您想将其作为 base64 编码字符串发送
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对不起。我是 php 新手,我一直在寻找教程并找到了这个脚本。它有这个“#91;;”在里面。这是什么意思。我认为它需要已上传图像的名称,图像将转换为字符串,然后转换为 Base_64。如果是这样,应该用什么替换“#91;;”??
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我认为时间戳在 onClick 中没有价值。我们仍然不知道什么是行不通的。代码乍一看还不错。我修复了你的 php.ini 文件。给出错误信息、细节...
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什么是固定的php??
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见问题中的 ^