【发布时间】:2016-08-05 22:49:29
【问题描述】:
所以我正在尝试使用 apache camel 访问简单的队列服务。
Java DSL 方法工作正常,但我尝试使用 xml 配置。
private AmazonSQS sqs;
sqs = new AmazonSQSClient(credentials);
Region sqsRegion = Region.getRegion(Regions.US_WEST_2);
sqs.setRegion(sqsRegion);
上面的代码运行良好,但我决定构建 bean。
<context:property-placeholder location="classpath:/default.properties" />
<bean name="sqsClient" class="com.amazonaws.services.sqs.AmazonSQSClient">
<constructor-arg>
<bean class="com.amazonaws.auth.BasicAWSCredentials">
<constructor-arg value="${access.key}"/>
<constructor-arg value="${secret.key}"/>
</bean>
</constructor-arg>
<property name="region" value="com.amazonaws.regions.Region"/>
</bean>
我遇到了一个错误
无法将 [java.lang.String] 类型的属性值转换为 属性“区域”所需的类型 [com.amazonaws.regions.Region]; 嵌套异常是 java.lang.IllegalStateException: 无法转换 [java.lang.String] 类型的值到所需类型 [com.amazonaws.regions.Region] 属性“区域”:无匹配 找到编辑器或转换策略
我还没有找到任何关于通过 Spring xml 配置 sqs 的信息。有时我认为 apache camel 已经过时或者没有人将它与 sqs 一起使用。 此外,下一步是连接在 Java DSL 实现中运行良好的扩展 SQS 库,但我不知道如何通过 xml 配置队列。
UPD:
感谢@jbird,我这样解决了问题:
<context:property-placeholder location="classpath:/default.properties" />
<bean id="awsRegion" class="org.springframework.beans.factory.config.MethodInvokingFactoryBean">
<property name="targetClass" value="com.amazonaws.regions.RegionUtils"/>
<property name="targetMethod" value="getRegion"/>
<property name="arguments">
<list>
<value>${aws.region}</value>
</list>
</property>
</bean>
<bean name="sqsClient" class="com.amazonaws.services.sqs.AmazonSQSClient">
<constructor-arg>
<bean class="com.amazonaws.auth.BasicAWSCredentials">
<constructor-arg value="${access.key}"/>
<constructor-arg value="${secret.key}"/>
</bean>
</constructor-arg>
<property name="region" ref="awsRegion"/>
</bean>
所以,我刚刚解析了我的 default.properties 文件,其中包含 aws.key、aws.secret 和区域设置。
我遇到了下一个问题。加载路由器等后Apache骆驼停止运行。
[ main] SpringCamelContext INFO Route: route1 started and consuming from: Endpoint[aws-sqs://queue?amazonSQSClient=%23sqsClient]
[ main] SpringCamelContext INFO Total 1 routes, of which 1 are started.
[ main] SpringCamelContext INFO Apache Camel 2.17.2 (CamelContext: camel-1) started in 6.105 seconds
Process finished with exit code 0
路由器:
import org.apache.camel.builder.RouteBuilder;
import org.springframework.stereotype.Component;
@Component
public class MyRouteBuilder extends RouteBuilder {
public void configure() {
from("aws-sqs://queue?amazonSQSClient=#sqsClient")
.log("We have a message! ${body}")
.to("file:target/output?fileName=login-message-${date:now:MMDDyy-HHmmss}.json");
}
}
还有camel-context.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://camel.apache.org/schema/spring http://camel.apache.org/schema/spring/camel-spring.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd
">
<context:property-placeholder location="classpath:/default.properties" />
<bean id="awsRegion" class="org.springframework.beans.factory.config.MethodInvokingFactoryBean">
<property name="targetClass" value="com.amazonaws.regions.RegionUtils"/>
<property name="targetMethod" value="getRegion"/>
<property name="arguments">
<list>
<value>${aws.region}</value>
</list>
</property>
</bean>
<bean name="sqsClient" class="com.amazonaws.services.sqs.AmazonSQSClient">
<constructor-arg>
<bean class="com.amazonaws.auth.BasicAWSCredentials">
<constructor-arg value="${access.key}"/>
<constructor-arg value="${secret.key}"/>
</bean>
</constructor-arg>
<property name="region" ref="awsRegion"/>
</bean>
<!-- enable Spring @Component scan -->
<context:component-scan base-package="com.test.router"/>
<camelContext xmlns="http://camel.apache.org/schema/spring">
<contextScan/>
</camelContext>
</beans>
【问题讨论】:
标签: java xml amazon-web-services apache-camel