Spring：找不到带有 URI 的 HTTP 请求的映射 [重复]

Question

我很难获得一个基本的 jsp 文件以在我的浏览器中呈现。我让它工作正常，但后来我尝试制作一个 header.jsp 和一个 footer.jsp 文件以包含在我的 student.jsp 文件中。当我把它抽象出来时，我就开始遇到问题了。

我是 Spring MVC 的新手，非常感谢您耐心等待 :)

我去的时候报错：localhost:8080/myprojectStudentCourses/student

从控制台是：

2014 年 12 月 6 日下午 12:52:37 org.springframework.web.servlet.PageNotFound noHandlerFound 警告：未找到带有 URI 的 HTTP 请求的映射 [/myprojectStudentCourses/WEB-INF/jsp/student.jsp] 在 名称为“myprojectStudentCourses”的 DispatcherServlet

myproject-servlet.xml

<beans xmlns="http://www.springframework.org/schema/beans"
   xmlns:context="http://www.springframework.org/schema/context"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="
   http://www.springframework.org/schema/beans     
   http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
   http://www.springframework.org/schema/context 
   http://www.springframework.org/schema/context/spring-context-3.0.xsd">

   <context:component-scan base-package="com.myproject" />

   <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
      <property name="prefix" value="/WEB-INF/jsp/" />
      <property name="suffix" value=".jsp" />
   </bean>

</beans>

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:web="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" id="WebApp_ID" version="2.4">
  <display-name>myproject Student Courses</display-name>
  <servlet>
    <servlet-name>myprojectStudentCourses</servlet-name>
    <servlet-class>
           org.springframework.web.servlet.DispatcherServlet
        </servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>myprojectStudentCourses</servlet-name>
    <url-pattern>/*</url-pattern>
  </servlet-mapping>
  <servlet-mapping>
    <servlet-name>myprojectStudentCourses</servlet-name>
    <url-pattern>*.jsp</url-pattern>
  </servlet-mapping>
</web-app>

student.jsp

<%@taglib uri="http://www.springframework.org/tags/form" prefix="form"%>
<%@include file="header.jsp" %>
<form:form method="POST" action="/myprojectStudentCourses/addStudent">
   <table>
    <tr>
        <td><form:label path="name">Name</form:label></td>
        <td><form:input path="name" /></td>
    </tr>
    <tr>
        <td><form:label path="age">Age</form:label></td>
        <td><form:input path="age" /></td>
    </tr>
    <tr>
        <td><form:label path="id">id</form:label></td>
        <td><form:input path="id" /></td>
    </tr>
    <tr>
        <td colspan="2">
            <input type="submit" value="Submit"/>
        </td>
    </tr>
</table>  
</form:form>
<%@include file="footer.jsp" %>

控制器

package com.myproject;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.ModelAttribute;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.ui.ModelMap;

@Controller
public class StudentController {

   @RequestMapping(value = "/student", method = RequestMethod.GET)
   public ModelAndView student() {
      return new ModelAndView("student", "command", new Student());
   }

   @RequestMapping(value = "/addStudent", method = RequestMethod.POST)
   public String addStudent(@ModelAttribute("SpringWeb")Student student, 
   ModelMap model) {
      model.addAttribute("name", student.getName());
      model.addAttribute("age", student.getAge());
      model.addAttribute("id", student.getId());

      return "result";
   }
}

Answer 1

感谢 Angad 和 zawhtut，我将 web.xml 更改为以下内容，并且可以正常工作！

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:web="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" id="WebApp_ID" version="2.4">
  <display-name>myproject Student Courses</display-name>
  <servlet>
    <servlet-name>myprojectStudentCourses</servlet-name>
    <servlet-class>
           org.springframework.web.servlet.DispatcherServlet
        </servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>myprojectStudentCourses</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>
</web-app>