如果单元格/列已为 Selenium webdriver TestNG 启用下拉列表，则无法读取 excel

Question

我正在使用以下函数从 excel 中读取数据以进行 selenium webdriver 测试。由于数据表有数百行要执行，因此需要下拉菜单来选择特定单元格的值，这使用户更容易在数据表中填写数据。我已使用数据验证列表为 Excel 工作表中的单元格启用下拉菜单。但是如果我尝试执行测试保存它后，我会得到下面给出的错误。如果我从数据表中删除下拉列表选项，它工作正常。 请帮忙，因为我必须在 excel 中为多个单元格值提供下拉菜单，以便轻松输入数据。

    package  functional_libraries;  
    import java.io.File;
    import java.io.FileInputStream;
    import java.io.IOException;
    import org.apache.poi.xssf.usermodel.XSSFCell;
    import org.apache.poi.xssf.usermodel.XSSFRow;
    import org.apache.poi.xssf.usermodel.XSSFSheet;
    import org.apache.poi.xssf.usermodel.XSSFWorkbook;
    import org.testng.annotations.*; 
    public class excelNew {  @Test
    public static String[][] excelRead(String filename, String Sheetname) throws 

IOException  {
        File excel = new File(filename);
        FileInputStream fis = new FileInputStream(excel);
        XSSFWorkbook wb = new XSSFWorkbook(fis);
        XSSFSheet ws = wb.getSheet(Sheetname) ;

        int rowNum = ws.getLastRowNum() + 1 ;
        int colNum = ws.getRow(0).getLastCellNum() ;
        String[][] data = new String[rowNum][colNum] ;


        for  ( int i = 0 ; i < rowNum ; i++) {
            XSSFRow row = ws.getRow(i) ;
                for ( short j = 0 ; j < colNum ; j++) {
                    XSSFCell cell = row.getCell(j) ;
                    String value = cellToString(cell);
                    data[i][j] = value ;
                    }
            }

        return data ;

        }

    @Test
    public static String cellToString(XSSFCell cell) {

    int type;
    Object result ;
    type = cell.getCellType();

    switch (type) {

        case 0 : // numeric value in Excel
            result = cell.getNumericCellValue() ;
            break ;
        case 1 : // String Value in Excel 
            result = cell.getStringCellValue() ;
            break ;
        case 3 : // Blank Cell 
          result = "";
          break;

        default :  
            throw new RuntimeException("There are no support for this type of cell") ;                      
    }

    return result.toString() ;
    }

}

[TestNG] 运行： C:\Users\suhail\AppData\Local\Temp\testng-eclipse-1517048838\testng-customsuite.xml

FAILED: TestClaimEntry
java.lang.NullPointerException
    at functional_libraries.excelNew.excelRead(excelNew.java:31)
    at testSet.TestClaimEntry.TestClaimEntry(TestClaimEntry.java:42)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at org.testng.internal.MethodInvocationHelper.invokeMethod(MethodInvocationHelper.java:84)
    at org.testng.internal.Invoker.invokeMethod(Invoker.java:714)
    at org.testng.internal.Invoker.invokeTestMethod(Invoker.java:901)
    at org.testng.internal.Invoker.invokeTestMethods(Invoker.java:1231)
    at org.testng.internal.TestMethodWorker.invokeTestMethods(TestMethodWorker.java:127)
    at org.testng.internal.TestMethodWorker.run(TestMethodWorker.java:111)
    at org.testng.TestRunner.privateRun(TestRunner.java:767)
    at org.testng.TestRunner.run(TestRunner.java:617)
    at org.testng.SuiteRunner.runTest(SuiteRunner.java:334)
    at org.testng.SuiteRunner.runSequentially(SuiteRunner.java:329)
    at org.testng.SuiteRunner.privateRun(SuiteRunner.java:291)
    at org.testng.SuiteRunner.run(SuiteRunner.java:240)
    at org.testng.SuiteRunnerWorker.runSuite(SuiteRunnerWorker.java:52)
    at org.testng.SuiteRunnerWorker.run(SuiteRunnerWorker.java:86)
    at org.testng.TestNG.runSuitesSequentially(TestNG.java:1224)
    at org.testng.TestNG.runSuitesLocally(TestNG.java:1149)
    at org.testng.TestNG.run(TestNG.java:1057)
    at org.testng.remote.RemoteTestNG.run(RemoteTestNG.java:111)
    at org.testng.remote.RemoteTestNG.initAndRun(RemoteTestNG.java:204)
    at org.testng.remote.RemoteTestNG.main(RemoteTestNG.java:175)

Answer 1

我找到了这个问题的解决方案。如果有人想使用，下面是代码。

package functional_libraries;

import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.util.Iterator;
import org.apache.poi.ss.usermodel.Cell;
import org.apache.poi.ss.usermodel.Row;
import org.apache.poi.xssf.usermodel.XSSFSheet;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;
import org.testng.annotations.Test;

public class excelitr {

  @Test
  public static String[][] excelRead(String filename, String Sheetname) throws IOException  {
        File excel = new File(filename);
            FileInputStream fis = new FileInputStream(excel);
            XSSFWorkbook wb = new XSSFWorkbook(fis);
            XSSFSheet ws = wb.getSheet(Sheetname) ;
            //Iterate through each rows one by one
            Iterator<Row> rowIterator = ws.iterator();
            int rowNum = ws.getLastRowNum() + 1 ;
            //int colNum = ws.getRow(0).getLastCellNum() ;
            int colNum = ws.getRow(0).getLastCellNum() +1 ;
            String[][] data = new String[rowNum][colNum] ;

            int i=0;
            while (rowIterator.hasNext())
            {
                   Row row = rowIterator.next();
                   //For each row, iterate through all the columns
                   Iterator<Cell> cellIterator = row.cellIterator();
                   int j = 0;

                   while (cellIterator.hasNext())
                   {

                       Cell cell = cellIterator.next();
                          //Check the cell type and format accordingly
                        String value = cellToString(cell);
                       // System.out.println(value +i +j);
                        data[i][j] = value ;
                    j++;

                   }
                   i++;
            }
      return data;
  }

  @Test
            public static String cellToString(Cell cell) {

            int type;
            Object result ;
            type = cell.getCellType();

            switch (type) {

                case 0 : // numeric value in Excel
                    result = cell.getNumericCellValue() ;
                    break ;
                case 1 : // String Value in Excel 
                    result = cell.getStringCellValue() ;
                    break ;
                case 3 : // Blank Cell 
                  result = "";
                  break;

                default :  
                    throw new RuntimeException("There are no support for this type of cell") ;                      
            }

            return result.toString() ;
            }
}