【问题标题】:Regular Expression for Mail Header Message邮件标题消息的正则表达式
【发布时间】:2011-07-24 00:25:59
【问题描述】:

我有一个邮箱文件,其中包含超过 50 兆的消息,由以下内容分隔:

从 - 2007 年 7 月 19 日星期四 07:11:55

我想在 Java 中为此构建一个正则表达式来一次提取每封邮件,所以我尝试使用扫描仪,使用以下模式作为分隔符:

public boolean ParseData(DataSource data_source) {

    boolean is_successful_transfer = false;
    String mail_header_regex = "^From\\s";
    LinkedList<String> ip_addresses = new LinkedList<String>();
    ASNRepository asn_repository = new ASNRepository();

    try {       

    Pattern mail_header_pattern = Pattern.compile(mail_header_regex);

    File input_file = data_source.GetInputFile();

    //parse out each message from the mailbox
    Scanner scanner = new Scanner(input_file);      

    while(scanner.hasNext(mail_header_pattern)) {


    String current_line = scanner.next(mail_header_pattern);

    Matcher mail_matcher = mail_header_pattern.matcher(current_line);

        //read each mail message and extract the proper "received from" ip address 
        //to put it in our list of ip's we can add to the database to prepare
        //for querying.
        while(mail_matcher.find()) {
            String message_text = mail_matcher.group();                 
            String ip_address = get_ip_address(message_text);

            //empty ip address means the line contains no received from
            if(!ip_address.trim().isEmpty()) 
                ip_addresses.add(ip_address);
        }

    }//next line

        //add ip addresses from mailbox to database 
        is_successful_transfer = asn_repository.AddIPAddresses(ip_addresses);           

    }

    //error reading file--unsuccessful transfer
    catch(FileNotFoundException ex) {
        is_successful_transfer = false;
    }

    return is_successful_transfer;

}

这似乎应该可以工作,但是每当我运行它时,程序就会挂起,可能是因为它没有找到模式。相同的正则表达式在 Perl 中使用相同的文件,但在 Java 中它总是挂在 String current_line = scanner.next(mail_header_pattern);

这个正则表达式正确还是我解析文件不正确?

【问题讨论】:

    标签: java regex java.util.scanner


    【解决方案1】:

    我会倾向于更简单的东西,只需阅读,如下所示:

    while(scanner.hasNextLine()) {
        String line = scanner.nextLine();
        if (line.matches("^From\\s.*")) {
           // it's a new email
        } else {
           // it's still part of the email body
        }
    }
    

    【讨论】:

    • 是的,尽管 string.split() (并用换行符替换 ^ 并用换行符结束)可能是一个更简单的解决方案。
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