正则表达式查找带方括号的字符串并替换

Question

我当前的代码是

`
String text= "[School_Teacher_Name] is our new member, So please congratulate [School_Teacher_Name] .";
String tag = "[School_Teacher_Name]";
String value= "Yash Mathur";
String str1 = tag.substring(1, tag.length()-1);
String reg = "/\\["+str1+"\\]/";

if(text.contains(tag)){
   return text.replaceAll(reg, value).trim();
}
else{
   return text;
}`

我在正则表达式方面没有太多经验。我的代码没有替换任何值，请帮帮我。

Answer 1

如果我没有误解你的要求，那么你可以这样做。 Regex

Java

import java.util.regex.Matcher;
import java.util.regex.Pattern;

final String regex = "\\[(School_Teacher_Name)]";
final String string = "[School_Teacher_Name] is our new member, So please congratulate [School_Teacher_Name] .";
final String subst = "Yash Mathur";

final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
final Matcher matcher = pattern.matcher(string);

// The substituted value will be contained in the result variable
final String result = matcher.replaceAll(subst);

System.out.println("Substitution result: " + result);

Javascript

const regex = /\[(School_Teacher_Name)]/gm;
const str = `[School_Teacher_Name] is our new member, So please congratulate [School_Teacher_Name] .`;
const subst = `Yash Mathur`;

// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);

console.log('Substitution result: ', result);

Answer 2

从您的正则表达式中删除正斜杠。

改变

String reg = "/\\["+str1+"\\]/";

到

String reg = "\\["+str1+"\\]";

输出

Yash Mathur is our new member, So please congratulate Yash Mathur .

PS - 在这种情况下，最好使用text.replace(tag, value) 而不是text.replaceAll(reg, value)

Answer 3

Template Literals 更容易。

let teacher = 'Yash Mathur';
let test = `${teacher} is our new member, so please congratulate ${teacher}.`;

console.log(test);