【发布时间】:2020-04-16 10:32:14
【问题描述】:
我需要与战争一起提供任意文件。在 webapps/$project 中放在哪里,在 web.xml 中配置?
web.xml
<?xml version="1.0" encoding="UTF-8" ?>
<web-app
version="4.0"
xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://xmlns.jcp.org/xml/ns/javaee
http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd
"
>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>WEB-INF/classes/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.security.web.session.HttpSessionEventPublisher</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
</listener>
<filter>
<filter-name>httpMethodFilter</filter-name>
<filter-class>org.springframework.web.filter.HiddenHttpMethodFilter</filter-class>
<async-supported>true</async-supported>
</filter>
<filter-mapping>
<filter-name>httpMethodFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!--Spring MVC-->
<servlet>
<servlet-name>servlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
<async-supported>true</async-supported>
</servlet>
<!--End of Spring MVC-->
<servlet-mapping>
<servlet-name>servlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>20</session-timeout>
</session-config>
</web-app>
【问题讨论】: