SQL Server 选择阶段/序列丢失或乱序的位置

Question

我有一张桌子，上面有families_id、date、metric_id

为每个 families_id 插入一条记录，将有一个 date 和 metric_id 1-10。

所以每个 families_id 应该有 10 条记录，这些记录会插入一个日期，每个记录都应该相互跟随。所以metric_id 10 日期应该大于metric_id 6 日期。

大规模我如何选择他们拥有的地方

1. 错过了metric_id
2. metric_id 6 的日期早于metric_id 2 的日期

Answer 1

使用 row_number 为每个家庭的 metric_id 和日期分配一个序数，然后它们应该匹配 - metric_id, 1,2,3,4... 也应该与其计算的 row_number() 匹配，还有 1,2， 3,4....

SELECT IQ.* FROM (SELECT families_id, [date], metric_id, 
        ROW_NUMBER() OVER (PARTITION BY families_id ORDER BY [date]) rn_date,
        ROW_NUMBER() OVER (PARTITION BY families_id ORDER BY metricid) rn_metric FROM YourTable) IQ 
    WHERE IQ.rn_date != IQ.rn_metric;

--should detect wrongly ordered metric_ids
SELECT IQ.* FROM (SELECT families_id, [date], metric_id, 
        ROW_NUMBER() OVER (PARTITION BY families_id ORDER BY [date]) rn_date,
        ROW_NUMBER() OVER (PARTITION BY families_id ORDER BY metricid) rn_metric FROM YourTable) IQ 
    WHERE IQ.metric_id != IQ.rn_metric;

另一种可能性 - 检测日期较早的 metricID 以获取更高的 id

    SELECT y1.families_id, y1.metric_id FROM yourtable y1
                    WHERE 
                    EXISTS(SELECT 0 FROM yourtable y2 WHERE y1.families_id = y2.families_id 
                                                            AND
                                                            y2.date < y1.date 
                                                            AND
                                                            y2.metricid > y1.metricid)