Java：查找csv字符串A的值是否属于字符串B的模式答案

【问题标题】：Java : Find if values of csv string A is of the pattern of String BJava：查找csv字符串A的值是否属于字符串B的模式
【发布时间】：2021-03-19 06:50:47
【问题描述】：

我有一个包含逗号分隔值的最终字符串 acceptedList。

final String acceptedList = "ABC, HIJ/LMN, PQR1, XYZ";

另一个动态字符串 receivedList 也是一个 csv，作为我函数的输入。

String receivedList  = "ABC, PQR1";

如果 receivedList 中的值与acceptedList 中的值匹配（以任何顺序），它应该返回成功消息。

成功场景示例：

receivedList  = "ABC";
receivedList  = "HIJ/LMN, ABC";
receivedList  = "XYZ, PQR1, ABC";

失败场景示例：

receivedList  = "ABC, UNKNOWN";
receivedList  = "UNKNOWN";
receivedList  = "HIJ-LMN";

我已经实现了以下代码，它工作正常。有没有更好的方法来实现这一点？

public class Driver {

    final static String acceptedList = "ABC, HIJ/LMN, PQR1, XYZ";

    public static void main(String[] args) {
        String receivedList  = "ABC, PQR1";
        System.out.println(checkValues(receivedList));      
    }

    private static String checkValues(String receivedList) {
        List<String> acceptedListArray = Arrays.asList(acceptedList.split(", "));
        String[] receivedArray = receivedList.split(", ");
        for (String string : receivedArray) {
            if (!acceptedListArray.contains(string)) {
                return "Error!";
            }
        }
        return "Success!";
    }
}

输出

Success!

【问题讨论】：

如果可以使用list提供的库函数，则不需要循环。

标签： java arrays arraylist

【解决方案1】：

`Set#containsAll`

我建议您将值存储在集合中以避免再次处理重复值，然后使用Set#containsAll 检查receivedList 中的所有值是否存在于acceptedList 中。

演示：

import java.util.Arrays;
import java.util.HashSet;
import java.util.Set;

public class Driver {

    final static String acceptedList = "ABC, HIJ/LMN, PQR1, XYZ";

    public static void main(String[] args) {
        String receivedList = "ABC, PQR1";
        System.out.println(checkValues(receivedList));

        receivedList = "ABC, UNKNOWN";
        System.out.println(checkValues(receivedList));
    }

    private static String checkValues(String receivedList) {
        Set<String> acceptedListSet = new HashSet<>(Arrays.asList(acceptedList.split(", ")));
        Set<String> receeivedListSet = new HashSet<>(Arrays.asList(receivedList.split(", ")));

        return acceptedListSet.containsAll(receeivedListSet) ? "Success!" : "Failure!";
    }
}

输出：

Success!
Failure!

【讨论】：

【解决方案2】：

您可以使用String#split 将两个 CSV 输入转换为数组。然后，将它们转换为列表并使用List#containsAll 进行断言：

public class Driver {
    final static String acceptedCSV = "ABC, HIJ/LMN, PQR1, XYZ";

    public static void main(String[] args) {
        String receivedCSV  = "ABC, PQR1";
        System.out.println(receivedCSV + " => " + checkValues(receivedCSV));      
        receivedCSV  = "ABC, DEF";
        System.out.println(receivedCSV + "  => " + checkValues(receivedCSV));      
    }

    private static String checkValues(String receivedCSV) {
        List<String> acceptedList = Arrays.asList(acceptedCSV.split("\\s*,\\s*"));
        List<String> receivedList = Arrays.asList(receivedCSV.split("\\s*,\\s*"));

        return acceptedList.containsAll(receivedList) ? "Success!" : "Error!";
    }
}

打印出来：

ABC, PQR1 => Success!
ABC, DEF  => Error!

【讨论】：