【发布时间】:2021-03-11 13:11:46
【问题描述】:
大家好,我是新来的,也是安卓开发的新手, 首先,如果之前有人问过并回答过,我想道歉。 我正在尝试构建一个 android 应用程序,在用户个人资料中,我有 2 个用于性别、男性和女性的单选按钮。 我能够将所选单选按钮的值传递给 firebase 数据库。 这是我使用的代码:
saveUserProfile.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String dogBirthdate = displayDogBirthday.getText().toString();
String dogGender = radioBtnDogGender.getText().toString();
String dogNeutered = radioBtnNeutered.getText().toString();
String aboutTheDog = aboutDog.getText().toString();
progressBar.setVisibility(View.VISIBLE);
//userId = fireAuth.getCurrentUser().getUid();
documentReference = fireStore.collection("users").document(userId);
Map<String, Object> user = new HashMap<>();
user.put("dogBirthdate", dogBirthdate);
user.put("dogGender", dogGender);
user.put("dogNeutered", dogNeutered);
user.put("aboutDog", aboutTheDog);
这用于单选按钮选择
public void radioBtnGenderClick(View view) {
int radioBtnDogGenderId = radioGroupDogGender.getCheckedRadioButtonId();
radioBtnDogGender = (RadioButton) findViewById(radioBtnDogGenderId);
Toast.makeText(getBaseContext(),radioBtnDogGender.getText(),Toast.LENGTH_LONG).show();
}
我能够将性别值作为文本传回用户个人资料屏幕
userId = fireAuth.getCurrentUser().getUid();
documentReference = fireStore.collection("users").document(userId);
documentReference.addSnapshotListener(new EventListener<DocumentSnapshot>() {
@Override
public void onEvent(@Nullable DocumentSnapshot value, @Nullable FirebaseFirestoreException error) {
dogName.setText(value.getString("dogName"));
aboutDog.setText(value.getString("aboutDog"));
displayDogBirthday.setText(value.getString("dogBirthdate"));
String gender = value.getString("dogGender");
if (gender.equalsIgnoreCase("Male")){
radioBtnMale.setChecked(true);
}else if (gender.equalsIgnoreCase("Female")){
radioBtnFemale.setChecked(true);
}
当我转到编辑用户配置文件时,正确的单选按钮显示为选中,但是当我单击保存配置文件时,应用程序崩溃,就像没有选中单选按钮时一样。 如果我在编辑个人资料页面中重新单击相同的单选按钮,一切正常。
我怎样才能修复它,这样用户就不必重新单击单选按钮(除非他想更改选择),并且在保存配置文件时它会将该按钮识别为已选中?
我认为问题在于,当将单选按钮值传递给数据库时,使用了“radioBtnDogGender”,而当从数据库传回值时,使用了“radioBtmMale”/“radioBtnFemale”。
如何将值传递到“radioBtnDogGender”而不是特定的男性/女性单选按钮?
这是xml代码:
<RadioGroup
android:id="@+id/radioGroupDogGender"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:orientation="horizontal"
app:layout_constraintBottom_toBottomOf="parent"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintHorizontal_bias="0.488"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toTopOf="parent"
app:layout_constraintVertical_bias="0.459">
<RadioButton
android:id="@+id/radioBtnMale"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:onClick="radioBtnGenderClick"
android:text="Male" />
<RadioButton
android:id="@+id/radioBtnFemale"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:onClick="radioBtnGenderClick"
android:text="Female" />
</RadioGroup>
这是应用程序崩溃时的堆栈跟踪(按下保存配置文件而不重新单击单选按钮):
2021-03-11 14:54:59.303 13459-13459/com.example.loginandregfirebase E/AndroidRuntime: FATAL EXCEPTION: main
Process: com.example.loginandregfirebase, PID: 13459
java.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.CharSequence android.widget.RadioButton.getText()' on a null object reference
at com.example.loginandregfirebase.EditUserProfilePage$7.onClick(EditUserProfilePage.java:205)
at android.view.View.performClick(View.java:7448)
at com.google.android.material.button.MaterialButton.performClick(MaterialButton.java:1119)
at android.view.View.performClickInternal(View.java:7425)
at android.view.View.access$3600(View.java:810)
at android.view.View$PerformClick.run(View.java:28305)
at android.os.Handler.handleCallback(Handler.java:938)
at android.os.Handler.dispatchMessage(Handler.java:99)
at android.os.Looper.loop(Looper.java:223)
at android.app.ActivityThread.main(ActivityThread.java:7656)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:592)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:947)
正如我在 cmets 中提到的,Gender 单选按钮在新代码中运行良好,当我尝试对 Neutered 单选按钮实现相同的代码时,我遇到了一个新问题,Neutered 单选按钮保持空白,当我物理按下时在其中一个上,应用程序重新启动,同时将 Neutered 单选按钮留空,在 Neutered 下的 View profile 中显示“未指定” 这是 Gender 和 Neutered 单选按钮的代码
radioGroupDogGender.clearCheck();
radioGroupNeutered.clearCheck();
String gender = value.getString("dogGender");
if (gender == null || gender.equalsIgnoreCase("Unspecified gender")){
// gender unknown, leave unselected
radioGroupDogGender = null;
}else
if (gender.equalsIgnoreCase("Male")){
radioBtnMale.setChecked(true);
radioBtnDogGender = radioBtnMale;
}else if (gender.equalsIgnoreCase("Female")){
radioBtnFemale.setChecked(true);
radioBtnDogGender = radioBtnFemale;
}
String neutered = value.getString("dogNeutered");
if (neutered == null || neutered.equalsIgnoreCase("Unspecified")){
// neutered unknown, leave unselected
radioGroupNeutered = null;
}else
if (neutered.equalsIgnoreCase("Yes")){
radioBtnNeuteredYes.setChecked(true);
radioBtnNeutered = radioBtnNeuteredYes;
}else if (neutered.equalsIgnoreCase("No")){
radioBtnNeuteredNo.setChecked(true);
radioBtnNeutered = radioBtnNeuteredNo;
}
saveUserProfile.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String dogBirthdate = displayDogBirthday.getText().toString();
String dogGender = radioBtnDogGender != null ? radioBtnDogGender.getText().toString():"unspecified gender";
//String dogGender = radioBtnDogGender.getText().toString();
String dogNeutered = radioBtnNeutered != null ? radioBtnNeutered.getText().toString(): "unspecified";
//String dogNeutered = radioBtnNeutered.getText().toString();
String aboutTheDog = aboutDog.getText().toString();
progressBar.setVisibility(View.VISIBLE);
//userId = fireAuth.getCurrentUser().getUid();
documentReference = fireStore.collection("users").document(userId);
Map<String, Object> user = new HashMap<>();
user.put("dogBirthdate", dogBirthdate);
user.put("dogGender", dogGender);
user.put("dogNeutered", dogNeutered);
user.put("aboutDog", aboutTheDog);
public void radioBtnGenderClick(View view) {
int radioBtnDogGenderId = radioGroupDogGender.getCheckedRadioButtonId();
if (radioBtnDogGenderId == -1){
//gender deselected
Toast.makeText(getBaseContext(),"gender deselected", Toast.LENGTH_LONG).show();
}else {
radioBtnDogGender = (RadioButton) findViewById(radioBtnDogGenderId);
Toast.makeText(getBaseContext(), radioBtnDogGender.getText(), Toast.LENGTH_LONG).show();
}
}
public void radioBtnNeutered(View view) {
int radioBtnNeuteredId = radioGroupNeutered.getCheckedRadioButtonId();
if (radioBtnNeuteredId == -1){
Toast.makeText(getBaseContext(),"neutered deselected",Toast.LENGTH_LONG).show();
}else {
radioBtnNeutered = (RadioButton) findViewById(radioBtnNeuteredId);
Toast.makeText(getBaseContext(), radioBtnNeutered.getText(), Toast.LENGTH_LONG).show();
}
}
我是不是忘记了什么,或者 Neutered 单选按钮需要不同的代码?
【问题讨论】:
-
如果应用程序崩溃,会有一个堆栈跟踪。请在 logcat 上查找,并将其添加到您的问题中。
标签: java android firebase google-cloud-firestore