【发布时间】:2020-08-01 11:28:39
【问题描述】:
我有一个Spring-MVC 在线商店项目,我使用Spring Boot 和Hibernate。我决定使用Specification 进行过滤。因此,我使用 JOINS 为规范编写了一个方法。请告诉我如何在没有 JOIN 的情况下编写相同的方法。
TeaSpecification 类:
public static Specification<Tea> getTeasByFilter(Long colorId, Long typeId, Long countryId) {
return (root, query, criteriaBuilder) -> {
Join<Object, Object> colorJoin = root.join(Tea_.TEA_COLOR);
Join<Object, Object> typeJoin = root.join(Tea_.TEA_TYPE);
Join<Object, Object> countryJoin = root.join(Tea_.COUNTRIES);
Predicate countryPredicate = criteriaBuilder.equal(countryJoin.get(Countries_.ID), countryId);
Predicate colorPredicate = criteriaBuilder.equal(colorJoin.get(TeaColor_.ID), colorId);
Predicate typePredicate = criteriaBuilder.equal(typeJoin.get(TeaColor_.ID), typeId);
return criteriaBuilder.and(colorPredicate, typePredicate, countryPredicate);
};
}
饮料类(茶扩展饮料):
@Inheritance(strategy = InheritanceType.JOINED)
public class Drink {
// Fields
//
private @Id
@GeneratedValue
Long id;
private String name;
private BigDecimal price;
private String about;
@Column(name = "is_deleted")
private boolean isDeleted;
// Relationships
//
@ManyToOne
@JoinColumn(name = "packaging_id")
private Packaging packaging;
@ManyToOne
@JoinColumn(name = "manufacturer_id")
private Manufacturer manufacturer;
@ManyToOne
@JoinColumn(name = "country_id")
private Countries countries;
}
public class Tea extends Drink {
// Relationships
//
@ManyToOne
@JoinColumn(name = "type_id")
private TeaType teaType;
@ManyToOne
@JoinColumn(name = "color_id")
private TeaColor teaColor;
}
【问题讨论】:
标签: java hibernate spring-mvc spring-data-jpa specifications