将字符串数组列表拆分为其原始字符串元素

Question

所以我有这个 Arraylist：

ArrayList<String> al = new ArrayList<String>();
for (int i = 0; i < arr1.length(); i++) {
JSONObject objectt = arr1.getJSONObject(i);
JSONObject triple = objectt.getJSONObject("triple");
String subject=triple.getString("s");
String predicate=triple.getString("p");
String value=triple.getString("o");
al.add(subject);
al.add(predicate);
al.add(value);
}

我想知道是否有办法将数组列表“al”拆分为 for 循环之外的原始字符串（主题、谓词、值）？

Answer 1

不要单独存储单个字符串，将它们存储在具有主题、谓词和值字段的对象中，如下所示：

public class Triple {
    private String subject;
    private String predicate;
    private String value;

    public Triple(String subject, String predicate, String value) {
        this.subject = subject;
        this.predicate = predicate;
        this.value = value;
    }

    /* getters, toString, equals and hashCode if necessary... */
}

// . . .
    List<Triple> al = new ArrayList<>();
    for (int i = 0; i < arr1.length(); i++) {
        JSONObject triple = arr1.getJSONObject(i).getJSONObject("triple");
        String subject = triple.getString("s");
        String predicate = triple.getString("p");
        String value = triple.getString("o");
        al.add(new Triple(subject, predicate, value));
    }

然后，如果您想使用这些值，请调用 getter：

// . . .
    for (Triple t : al) {
        String subject = t.getSubject();
        String predicate = t.getPredicate();
        String value = t.getValue();
        // do something with them
    }