【发布时间】:2017-09-28 06:17:19
【问题描述】:
我有一个非常大的 XML 字符串。我在这里只发布了 XML 对象的一部分。我正在尝试将此 XML 转换为 Java 对象。我的第一个问题是,我是否需要创建全部 XML 标记值的 Java 对象,还是只创建选定的内部 XML 对象的 Java 对象?请找到我的 XML 字符串。
<DATAPACKET REQUEST-ID = "2">
<HEADER>
<RESPONSE-TYPE CODE="1" DESCRIPTION="Response DataPacket"/>
<SEARCH-RESULT-LIST>
<SEARCH-RESULT-ITEM>
<NAME MATCHED="TRUE"/>
</SEARCH-RESULT-ITEM>
</SEARCH-RESULT-LIST>
</HEADER>
<BODY>
<CONS_SCORE>
<SCORE>0</SCORE>
<REASON1>
<HEADER></HEADER>
<DESCRIPTION></DESCRIPTION>
</REASON1>
<REASON2>
<HEADER></HEADER>
<DESCRIPTION></DESCRIPTION>
</REASON2>
<REASON3>
<HEADER></HEADER>
<DESCRIPTION></DESCRIPTION>
</REASON3>
<REASON4>
<HEADER></HEADER>
<DESCRIPTION></DESCRIPTION>
</REASON4>
</CONS_SCORE>
<CONSUMER_PROFILE2>
<CONSUMER_DETAILS2>
<RUID>1234</RUID>
<NAME>ABC</NAME>
<DATE_OF_BIRTH>1980-03-03T00:00:00+03:00</DATE_OF_BIRTH>
<GENDER>001</GENDER>
</CONSUMER_DETAILS2>
<ID_DETAILS2>
<SLNO>1</SLNO>
<SOURCE_ID>001</SOURCE_ID>
<ID_VALUE>2806</ID_VALUE>
<EXP_DATE>2018-07-13T00:00:00+03:00</EXP_DATE>
</ID_DETAILS2>
</CONSUMER_PROFILE2>
</BODY>
</DATAPACKET>
在上面的对象中,我只想获取 CONSUMER_PROFILE2 对象。这是我的 Dto 课程
@XmlRootElement(name = "DATAPACKET")
public class ConsumerProfileDto {
private ConsumerDetailsDto CONSUMER_DETAILS2;
private IdDetailsDto ID_DETAILS2;
public ConsumerDetailsDto getCONSUMER_DETAILS2() {
return CONSUMER_DETAILS2;
}
public void setCONSUMER_DETAILS2(ConsumerDetailsDto cONSUMER_DETAILS2) {
CONSUMER_DETAILS2 = cONSUMER_DETAILS2;
}
public IdDetailsDto getID_DETAILS2() {
return ID_DETAILS2;
}
public void setID_DETAILS2(IdDetailsDto iD_DETAILS2) {
ID_DETAILS2 = iD_DETAILS2;
}
}
CONSUMER_DETAILS2 类
@XmlRootElement(name = "CONSUMER_DETAILS2")
public class ConsumerDetailsDto {
private String NAME;
private String DATE_OF_BIRTH;
private String GENDER;
private String NATIONALITY;
public String getNAME() {
return NAME;
}
public void setNAME(String nAME) {
NAME = nAME;
}
public String getDATE_OF_BIRTH() {
return DATE_OF_BIRTH;
}
public void setDATE_OF_BIRTH(String dATE_OF_BIRTH) {
DATE_OF_BIRTH = dATE_OF_BIRTH;
}
public String getGENDER() {
return GENDER;
}
public void setGENDER(String gENDER) {
GENDER = gENDER;
}
public String getNATIONALITY() {
return NATIONALITY;
}
public void setNATIONALITY(String nATIONALITY) {
NATIONALITY = nATIONALITY;
}
这是解组的代码
JAXBContext jaxbContext = JAXBContext.newInstance(ConsumerProfileDto.class);
StringReader reader = new StringReader(responseXML);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
ConsumerDetailsDto que= (ConsumerDetailsDto) jaxbUnmarshaller.unmarshal(reader);
System.out.println(que.getDATE_OF_BIRTH());
System.out.println(que.getGENDER());;
System.out.println(que.getNAME());
附言
我使用过 DocumentBuilder,并且能够使用它获取值。但是,我想使用 Jaxb 进行提取。
【问题讨论】:
标签: java xml jaxb unmarshalling