【发布时间】:2014-08-15 09:34:21
【问题描述】:
我正在使用这个JAXB Collection Generics 来解组我的字符串 xml 并返回 List 类型。 这是我使用的方法。
public static <T> List<T> unmarshalCollection(Class<T> cl, String s)
throws JAXBException {
return unmarshalCollection(cl, new StringReader(s));
}
public static <T> List<T> unmarshalCollection(Class<T> cl, Reader r)
throws JAXBException {
return unmarshalCollection(cl, new StreamSource(r));
}
private static <T> List<T> unmarshalCollection(Class<T> cl, Source s)
throws JAXBException {
JAXBContext ctx = JAXBContext.newInstance(JAXBCollection.class, cl);
Unmarshaller u = ctx.createUnmarshaller();
JAXBCollection<T> collection = u.unmarshal(s, JAXBCollection.class).getValue();
return collection.getItems();
}
getter 和 setter 示例:
@XmlRootElement(name = "person")
class Person{
private String firstName;
private String lastName;
private String address;
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getAddress() {
return address;
}
public void setAddress(String address) {
this.address = address;
}
@Override
public String toString() {
return "Person [firstName ="+firstName+" , lastName = "+lastName+" , address = "+address+"]";
}
}
主类:
public static void main(String[] args) throws JAXBException {
String xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><person><firstName>Foo</firstName><lastName>Bar</lastName><address>U.S</address></person>";
List<Person> p = unmarshalCollection(Person.class,xml);
for(Person person : p ){
System.out.println(person);
}
}
抛出异常
Exception in thread "main" java.lang.ClassCastException: org.apache.xerces.dom.ElementNSImpl cannot be cast to com.Person
at com.JAXBUtil.main(JAXBUtil.java:62)
我做错了什么?有什么想法吗?谢谢。
【问题讨论】:
标签: java xml xml-parsing jaxb