【发布时间】:2016-01-07 22:46:38
【问题描述】:
public static void main(String[] args) {
// TODO code application logic here
int[] age = new int []{21,20,19,18,18,};
String name [] = {"sofia","maria","john","Petra","mark"};
int sum = 0;
int avg;
int min=age[0];
int i;
int counter=0;
for(i=0;i<age.length;i++){
if(age[i]<min ) {
min=age[i];
}
avg= sum/age.length;
System.out.println("the avarage of all Students are :"+avg);
System.out.println("the minimum age of all Students : "+min);
}
for(i=0;i<age.length;i++){
if (age[i] == min ) {
System.out.println("the minimum age of all Students : "+name[i]);
}
}
}
} // 我们有学校的 (age) 和 (names) --> 找到 "john" 是学校的名字,如果有多个 "one john" 打印学生的所有年龄,则打印 "his age"打电话给“约翰”有人可以帮我解决这个问题吗?
【问题讨论】: