【发布时间】:2012-02-01 17:05:53
【问题描述】:
我正在开发一个 Java/J2EE Web 应用程序。数据的持久化由 JPA/TopLink 完成。我对这个实体有疑问:
@Entity
@Table(name = "articlecatalogue_has_article", catalog = "artisance", schema = "public")
@NamedQueries({@NamedQuery(name = "ArticlecatalogueHasArticle.findAll", query = "SELECT a FROM ArticlecatalogueHasArticle a"), @NamedQuery(name = "ArticlecatalogueHasArticle.findByArcIntId", query = "SELECT a FROM ArticlecatalogueHasArticle a WHERE a.articlecatalogueHasArticlePK.arcIntId = :arcIntId"), @NamedQuery(name = "ArticlecatalogueHasArticle.findByArtIntId", query = "SELECT a FROM ArticlecatalogueHasArticle a WHERE a.articlecatalogueHasArticlePK.artIntId = :artIntId"), @NamedQuery(name = "ArticlecatalogueHasArticle.findByAhaDecQuantite", query = "SELECT a FROM ArticlecatalogueHasArticle a WHERE a.ahaDecQuantite = :ahaDecQuantite"), @NamedQuery(name = "ArticlecatalogueHasArticle.findByAhaDecPrixvente", query = "SELECT a FROM ArticlecatalogueHasArticle a WHERE a.ahaDecPrixvente = :ahaDecPrixvente")})
public class ArticlecatalogueHasArticle implements Serializable {
private static final long serialVersionUID = 1L;
@EmbeddedId
protected ArticlecatalogueHasArticlePK articlecatalogueHasArticlePK;
@Column(name = "aha_dec_quantite")
private BigDecimal ahaDecQuantite;
@Column(name = "aha_dec_prixvente")
private BigDecimal ahaDecPrixvente;
@JoinColumn(name = "art_int_id", referencedColumnName = "art_int_id", insertable = false, updatable = false)
@ManyToOne(optional = false, fetch = FetchType.LAZY)
private Article article;
@JoinColumn(name = "arc_int_id", referencedColumnName = "arc_int_id", insertable = false, updatable = false)
@ManyToOne(optional = false, fetch = FetchType.LAZY)
private Articlecatalogue articlecatalogue;
还有多个主键:
@Embeddable
public class ArticlecatalogueHasArticlePK implements Serializable {
@Basic(optional = false)
@Column(name = "arc_int_id")
private int arcIntId;
@Basic(optional = false)
@Column(name = "art_int_id")
private int artIntId;
当我尝试使 ArticlecatalogueHasArticle 实体持久化时,出现以下错误:
Local Exception Stack:
Exception [TOPLINK-4002] (Oracle TopLink Essentials - 2.1 (Build b60e-fcs (12/23/2008))): oracle.toplink.essentials.exceptions.DatabaseException
Internal Exception: org.postgresql.util.PSQLException: ERREUR: une valeur NULL viole la contrainte NOT NULL de la colonne « arc_int_id »
Error Code: 0
Call: INSERT INTO artisance.public.articlecatalogue_has_article (aha_dec_prixvente, aha_dec_quantite, art_int_id, arc_int_id) VALUES (?, ?, ?, ?)
bind => [null, 1, null, null]
而我想要持久化的实体中的字段 arcIntId 和 artIntId 不为空。我认为问题是由于 ArticlecatalogueHasArticlePK 和 ArticlecatalogueHasArticle @JoinColumn 中的列“art_int_id”和“arc_int_id”的双重实例,但我不确定,我不知道如何解决问题。
感谢任何帮助。
【问题讨论】:
-
在尝试使实体持久化之前,您是否为
arcIntId和artIntId分配了值?发布导致异常的代码 sn-p 会有所帮助(在违规行之前有足够多的行以提供一些上下文)。 -
是的,我用调试器检查了值分配给
arcIntId和artIntId。当我执行em.persist(aha);时抛出异常,aha出现了 ArticlecatalogueHasArticle。
标签: java hibernate jakarta-ee jpa toplink