【问题标题】:Multiple foreign keys in one mapping class Hibernate+JPA+Spring一个映射类中的多个外键 Hibernate+JPA+Spring
【发布时间】:2016-05-10 10:30:50
【问题描述】:

我有 2 个类,分别称为 Client 和 Movie。我想要一个 RentedMovie 类,它包含客户端的外键和书籍的外键,并且它也有自己的 id。到目前为止,我的课程看起来都一样:

客户:

@Entity
@Table(name="Client")
public class Client implements Serializable {

    @Id
    @Column(name="id", nullable= false)
    private Integer id;

    @Column(name="age", nullable = false)
    private Integer age;

    @Column(name="numberofrentals", nullable = false)
    private Integer numberofrentals;

    @Column(name="name", nullable = false)
    private String name;

    @Column(name="address", nullable = false)
    private String address;

    public Client() {
    }

    public Client(Integer id, Integer age, Integer numberofrentals, String name, String address) {

        this.id = id;
        this.age = age;
        this.numberofrentals = numberofrentals;
        this.name = name;
        this.address = address;
    }

    public Integer getId() {

        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public Integer getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }

    public Integer getnumberofrentals() {
        return numberofrentals;
    }

    public void setnumberofrentals(int numberofrentals) {
        this.numberofrentals = numberofrentals;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getAddress() {
        return address;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;

        Client client = (Client) o;

        if (age != client.age) return false;
        if (numberofrentals != client.numberofrentals) return false;
        if (!id.equals(client.id)) return false;
        if (!name.equals(client.name)) return false;
        return address.equals(client.address);

    }

    @Override
    public int hashCode() {
        int result = id.hashCode();
        result = 31 * result + age;
        result = 31 * result + numberofrentals;
        result = 31 * result + name.hashCode();
        result = 31 * result + address.hashCode();
        return result;
    }

    public void setAddress(String address) {
        this.address = address;
    }

    @Override
    public String toString() {
        return "Client{" +
                "id=" + id +
                ", age=" + age +
                ", numberofrentals=" + numberofrentals +
                ", name='" + name + '\'' +
                ", address='" + address + '\'' +
                '}';
    }
}

电影:

@Entity
@Table(name="movie")
public class Movie  implements Serializable {

    @Id
    @Column(name="id", nullable=false)
    private Integer id;

    @Column(name="name", nullable = false)
    private String name;

    @Column(name="numberofrentals", nullable=false)
    private Integer numberofrentals;

    @Column(name="director", nullable = false)
    private String director;

    @Column(name="year", nullable = false)
    private Integer year;

    public Movie() {
    }

    public Movie(Integer id, String name, Integer numberofrentals, String director, Integer year) {
        this.id = id;
        this.name = name;
        this.numberofrentals = numberofrentals;
        this.director = director;
        this.year = year;
    }

    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getDirector() {
        return director;
    }

    public void setDirector(String director) {
        this.director = director;
    }

    public Integer getYear() {
        return year;
    }

    public void setYear(Integer year) {
        this.year = year;
    }

    public Integer getNumberofrentals() {
        return numberofrentals;
    }

    public void setNumberofrentals(Integer numberofrentals) {
        this.numberofrentals = numberofrentals;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;

        Movie movie = (Movie) o;

        if (!id.equals(movie.id)) return false;
        if (!name.equals(movie.name)) return false;
        if (!numberofrentals.equals(movie.numberofrentals)) return false;
        if (!director.equals(movie.director)) return false;
        return year.equals(movie.year);

    }

    @Override
    public int hashCode() {
        int result = id.hashCode();
        result = 31 * result + name.hashCode();
        result = 31 * result + numberofrentals.hashCode();
        result = 31 * result + director.hashCode();
        result = 31 * result + year.hashCode();
        return result;
    }

    @Override
    public String toString() {
        return "Movie{" +
                "id=" + id +
                ", name='" + name + '\'' +
                ", numberofrentals=" + numberofrentals +
                ", director='" + director + '\'' +
                ", year=" + year +
                '}';
    }
}

还有现在正常的租用班级:

@Entity
@Table(name="rented")
public class Rented implements Serializable {
    @Id
    @Column(name="id", nullable= false)
    private Integer id;

    @Column(name="movieID", nullable = false)
    private Integer movieID;

    @Column(name="clientID", nullable = false)
    private Integer clientID;

    public Rented(Integer id, Integer movieID, Integer clientID) {
        this.id = id;
        this.movieID = movieID;
        this.clientID = clientID;
    }

    public Rented() {
    }

    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public Integer getMovieID() {
        return movieID;
    }

    public void setMovieID(Integer movieID) {
        this.movieID = movieID;
    }

    public Integer getClientID() {
        return clientID;
    }

    public void setClientID(Integer clientID) {
        this.clientID = clientID;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;

        Rented rented = (Rented) o;

        if (!id.equals(rented.id)) return false;
        if (!movieID.equals(rented.movieID)) return false;
        return clientID.equals(rented.clientID);

    }

    @Override
    public int hashCode() {
        int result = id.hashCode();
        result = 31 * result + movieID.hashCode();
        result = 31 * result + clientID.hashCode();
        return result;
    }

    @Override
    public String toString() {
        return "Rented{" +
                "id=" + id +
                ", movieID=" + movieID +
                ", clientID=" + clientID +
                '}';
    }
}

我真正需要改变什么?我需要给 Rented 班级一部电影和一个客户?客户和书之间是一对多的关系。一本书只能租一次,一个客户可以租多本书。我是否必须在某个地方保留列表,或者租用的班级会是什么样子,另外两个班级我还需要改变什么?

【问题讨论】:

    标签: java spring hibernate jpa


    【解决方案1】:

    首先您应该将Rented 类中的clientId 更改为private client Client。 接下来,您必须为此字段添加注释@ManyToOne。接下来,您必须对字段 movieId 执行相同的操作。 当然,您必须更改构造函数、getter 和 setter。

    【讨论】:

    • 当然可以,但这是否足够?其他两个没有变化?
    • 如果您需要从电影访问租用实例列表 -> 是的,但如果您只需要从租用实例访问电影和客户端就足够了。如果您需要更多信息,可以阅读有关 hibernate 中的单向和双向关系的信息。
    【解决方案2】:

    您的映射应如下所示(省略其他字段)。始终考虑对象而不是实体字段。

    @Entity
    @Table(name="rental")
    public class Rental implements Serializable {
    
        @Id
        @Column(name="id", nullable= false)
        private Integer id;
    
        //movie associated with this rental
        @ManyToOne
        @JoinColumn(name="movieID", nullable = false)
        private Movie movie;
    
        //client associated with this rental
        @ManyToOne
        @JoinColumn(name="clientID", nullable = false)
        private Client client;
    }
    
    @Entity
    @Table(name="movie")
    public class Movie  implements Serializable {
    
        //collection of rentals for this movie
        @OneToMany(mappedBy = "movie")
        private Set<Rental> rentals;
    }
    
    @Entity
    @Table(name="client")
    public class Client implements Serializable {
    
        //collection of rentals for this client
        @OneToMany(mappedBy = "client")
        private Set<Rental> rentals;
    }
    

    这是一个基本的双向一对多映射,您可以在此处了解更多信息:

    https://en.wikibooks.org/wiki/Java_Persistence/OneToMany#Example_of_a_OneToMany_relationship_and_inverse_ManyToOne_annotations

    【讨论】:

    • 所以我的班级有一组出租...我需要创建函数来实际添加到这些列表中还是什么?
    • 是的。创建添加/删除租赁方法,并且不允许直接修改集合。保持内存模型一致很重要。例如:stackoverflow.com/a/26220097/1356423
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