【问题标题】:Iteration to create createCriteria. Getting error org.hibernate.QueryException: duplicate association path迭代创建 createCriteria。获取错误 org.hibernate.QueryException:重复关联路径
【发布时间】:2016-06-30 23:47:27
【问题描述】:

我有一张图片表,每张图片都与一张画廊表有多对多的关系。我正在尝试使用org.hibernate.Criteria 返回链接给定画廊列表的所有图像。

我一直在尝试以下方法,我循环遍历画廊列表并为每个画廊创建一个新的createCriteria(例如,每个所需画廊一个内部连接),这仅适用于一个画廊。但是,当我尝试多个时,我得到一个 org.hibernate.QueryException: duplicate association path: galleries 错误...

ImagesDAOCustom.java

public Images getRandomImagesInGallerys(String[] galleryList) {             
        Session session = sessionFactory.getCurrentSession();
        Criteria criteria = session.createCriteria(Images.class, "image");
        // We want an image that is part of all galleries so we need to create
        // a join per gallery.
        for (String gallery: galleryList) {
            criteria.createCriteria("image.galleries", gallery);
            criteria.add(Restrictions.eq(gallery + ".name",gallery));
        }
        criteria.setProjection(Projections.distinct(Projections.property("id")));
        List<Integer> imageIdList = criteria.list();

        Images result;
        if (imageIdList.size() > 0) {
            int index = rand.nextInt(imageIdList.size());
            result = imagesDAO.findOne(imageIdList.get(index));
        } else {
            result = null;
        }
        return result;
    }

Images.java

public class Images  {

    @Id
    @GeneratedValue
    @Column(name="ugc_images_id")
    private int id;

    @JsonIgnore
    @JsonView(Views.Internal.class)
    @ManyToMany(fetch = FetchType.LAZY)
    @JoinTable(name="ugc_image_galleries", joinColumns={@JoinColumn(name="image_id")}, inverseJoinColumns={@JoinColumn(name="gallery_id")})
    private Set<Galleries> galleries = new HashSet<>();

    ...
}

Galleries.java

public class Galleries }

    @Id
    @GeneratedValue
    @Column(name="ugc_galleries_id")
    private int id;

    @JsonManagedReference
    @ManyToMany(mappedBy="galleries")    
    private Set<Images> images = new HashSet<>();

    @Column(name="name")
    private String name;

    ...

}

【问题讨论】:

  • 查看here 一种使用SqlRestrictionexists 的解决方法。

标签: java hibernate


【解决方案1】:

我遇到了同样的问题,我搜索了几个小时。

这对我有用:

public Images getRandomImagesInGallerys(String[] galleryList) {

    String query = "from Images ";
    boolean first = true;

    for(String string : galleryList) {
        if(first){
            query+="where '"+string+"' member of galleries ";
            first=false;
        } else {
            query+="or '"+string+"' member of galleries ";
        }
    }

    entityManager.createQuery(query, Images.class).getResultList();
}

希望对某人有所帮助。

【讨论】:

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