Hibernate-@OnetoMany 与 Collection 上的 Where 子句

Question

在我的一对多和多对一双向关系中，我想执行以下sql-

select * from user_credential c 
join user_profile p on c.login_id = p.login_id
join user_address a on p.address_id = a.address_id
where p.profile_id = 1

但是，我得到了 sql 的结果-

select * from user_credential c 
join user_profile p on c.login_id = p.login_id
join user_address a on p.address_id = a.address_id
where p.credential_id = 1

休眠实体详细信息-

    @Entity
    @Table(name = "user_credential")
    public class UserCredential implements Serializable {
        private static final long serialVersionUID = -2839071606927921689L;

        @Id
        @GeneratedValue(strategy = GenerationType.AUTO)
        @Column(name = "login_id", insertable = false, updatable = false, nullable = false)
        private int login_id = 0;

        @Column(name = "password", insertable = true, updatable = true, nullable = false)
        private String password = null;

        @OneToMany(mappedBy = "login_id", fetch = FetchType.EAGER, cascade = CascadeType.ALL)
        private Set<UserProfile> profiles = null;
//getters/setters
}

@Entity
@Table(name = "user_profile")
public class UserProfile implements Serializable {

    private static final long serialVersionUID = 5765280899633539336L;

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "profile_id", length = 10, insertable = false, updatable = false, nullable = false)
    private int profile_id = 0;

    @ManyToOne
    @JoinColumn(name = "login_id", insertable = true, updatable = true, nullable = false)
    private UserCredential login_id = null;

    @Column(name = "name", length = 20, insertable = true, updatable = true, nullable = false)
    private String name = null;

    @Column(name = "age", length = 3, insertable = true, updatable = true, nullable = false)
    private byte age = 0;

    @OneToMany(mappedBy = "profile_id", fetch = FetchType.EAGER, cascade = CascadeType.ALL)
    private Set<UserAddress> address = null;

//getters/setters
}

@Entity
@Table(name = "user_address")
public class UserAddress extends BaseTable{
    private static final long serialVersionUID = 5036341911955664992L;

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "address_id", length = 10, insertable = false, updatable = false, nullable = false)
    private int address_id = 0;

    @ManyToOne
    @JoinColumn(name = "profile_id", insertable = true, updatable = true, nullable = false)
    private UserProfile profile_id = null;

    @Column(name = "state", length = 20, insertable = true, updatable = true, nullable = false)
    private String state = null;

    @Column(name = "city", length = 20, insertable = true, updatable = true, nullable = false)
    private String city = null;
//getters/setters
}

HQL：

select credential from UserCredential credential
join credential.profiles profile
where  profile.profile_id = 1

我不明白，为什么 hibernate 过滤父 id 上的数据，以及我需要的 sql 将如何执行。我正在使用休眠 4.3.8

如果需要任何其他信息，请告知。

Answer 1

我会这样写查询：

select distinct c 
from Profile p
join p.login_id c
where p.profile_id = 1

删除重复项并从Child 加入Parent 可能会帮助您解决问题。