【发布时间】:2013-01-15 22:30:06
【问题描述】:
当鼠标双击时,我使用此代码片段在树上执行一些操作:打开一个窗口并获取鼠标双击的node,但它没有返回任何内容,它返回空:
MouseListener ml = new MouseAdapter() {
public void mousePressed(MouseEvent e) {
int selRow = contactTree.getRowForLocation(e.getX(), e.getY());
TreePath selPath = contactTree.getPathForLocation(e.getX(), e.getY());
System.out.println(contactTree.getEditingPath());
Account memberToChat;
if(selRow != -1) {
if(e.getClickCount() == 1) {
}
else if(e.getClickCount() == 2) {
new ChatWindow().setVisible(true);
memberToChat=(Account)node.getUserObject(); // node is declared somewhere in the class as DefaultMutableTreeNode node
System.out.println(memberToChat.getFirstName()+" "+memberToChat.getEmail());
}
}
}
};
【问题讨论】:
-
节点已“声明”,很好。但是它在哪里设置为当前选择?您还提到“返回null”。那个return语句在哪里?你应该澄清你的问题。
标签: java swing selection jtree