将 DefaultMutableTreeNode 分配给 JTree答案

【问题标题】：Assign DefaultMutableTreeNode to JTree将 DefaultMutableTreeNode 分配给 JTree
【发布时间】：2011-10-20 12:32:53
【问题描述】：

我正在 Netbeans 中开发一个小型桌面应用程序。我将JTree 拖放到我的JFrame 上，现在我想动态填充这个JTree 的节点层次结构。为此，我编写了一个返回我DefaultMutableTreeNode 对象的方法。现在我如何将此对象分配给我拖放的JTree

【问题讨论】：

标签： java swing netbeans jtree

【解决方案1】：

以下示例将帮助您做到这一点

package commondemo;
/**
*
* @author hemant
 */
 import java.awt.*;
 import javax.swing.*;
 import javax.swing.tree.*;

 public class SimpleTree extends JFrame {
 public static void main(String[] args) {
 new SimpleTree();
}

public SimpleTree() {
super("Creating a Simple JTree");


Container content = getContentPane();
Object[] hierarchy =
  { "javax.swing",
    "javax.swing.border",
    "javax.swing.colorchooser",
    "javax.swing.event",
    "javax.swing.filechooser",
    new Object[] { "javax.swing.plaf",
                   "javax.swing.plaf.basic",
                   "javax.swing.plaf.metal",
                   "javax.swing.plaf.multi" },
    "javax.swing.table",
    new Object[] { "javax.swing.text",
                   new Object[] { "javax.swing.text.html",
                                  "javax.swing.text.html.parser" },
                   "javax.swing.text.rtf" },
    "javax.swing.tree",
    "javax.swing.undo" };
DefaultMutableTreeNode root = processHierarchy(hierarchy);
JTree tree = new JTree(root);
content.add(new JScrollPane(tree), BorderLayout.CENTER);
setSize(275, 300);
setVisible(true);
}

/** Small routine that will make node out of the first entry
*  in the array, then make nodes out of subsequent entries
*  and make them child nodes of the first one. The process is
*  repeated recursively for entries that are arrays.
*/

private DefaultMutableTreeNode processHierarchy(Object[] hierarchy) {
 DefaultMutableTreeNode node =
   new DefaultMutableTreeNode(hierarchy[0]);
 DefaultMutableTreeNode child;
for(int i=1; i<hierarchy.length; i++) {
  Object nodeSpecifier = hierarchy[i];
  if (nodeSpecifier instanceof Object[])  // Ie node with children
    child = processHierarchy((Object[])nodeSpecifier);
  else
    child = new DefaultMutableTreeNode(nodeSpecifier); // Ie Leaf
  node.add(child);
}
return(node);
}
}

【讨论】：

我已经尝试了这两行，但在我的情况下它没有注意到。我还检查了根对象，它包含预期的值。 DefaultMutableTreeNode root = processHierarchy(hierarchy); JTree 树 = 新 JTree(根);还有其他建议吗？

【解决方案2】：

How to Use Trees

【讨论】：

您可以通过发布相关代码来改进此答案。