【发布时间】:2011-07-18 23:16:27
【问题描述】:
我有一个简短的程序,它通过向其中添加节点来生成链表,然后释放链表分配的内存。
Valgrind 不报告任何内存泄漏错误,但进程继续持有分配的内存。
只有在将分配的内存从 sizeof(structure_name) 更改为固定数字 512 后,我才能修复错误。(请参阅注释代码)
这是一个错误还是正常操作? 这是代码:
#include <execinfo.h>
#include <stdlib.h>
#include <stdio.h>
typedef struct llist_node {
int ibody;
struct llist_node * next;
struct llist_node * previous;
struct llist * list;
}llist_node;
typedef struct llist {
struct llist_node * head;
struct llist_node * tail;
int id;
int count;
}llist;
llist_node * new_lnode (void) {
llist_node * nnode = (llist_node *) malloc ( 512 );
// llist_node * nnode = (llist_node *) malloc ( sizeof(llist_node) );
nnode->next = NULL;
nnode->previous = NULL;
nnode->list = NULL;
return nnode;
}
llist * new_llist (void) {
llist * nlist = (llist *) malloc ( 512 );
// llist * nlist = (llist *) malloc ( sizeof(llist) );
nlist->head = NULL;
nlist->tail = NULL;
nlist->count = 0;
return nlist;
}
void add_int_tail ( int ibody, llist * list ) {
llist_node * nnode = new_lnode();
nnode->ibody = ibody;
list->count++;
nnode->next = NULL;
if ( list->head == NULL ) {
list->head = nnode;
list->tail = nnode;
}
else {
nnode->previous = list->tail;
list->tail->next = nnode;
list->tail = nnode;
}
}
void destroy_list_nodes ( llist_node * nodes ) {
llist_node * llnp = NULL;
llist_node * llnpnext = NULL;
llist_node * llnp2 = NULL;
if ( nodes == NULL )
return;
for ( llnp = nodes; llnp != NULL; llnp = llnpnext ) {
llnpnext = llnp->next;
free (llnp);
}
return;
}
void destroy_list ( llist * list ) {
destroy_list_nodes ( list->head );
free (list);
}
int main () {
int i = 0;
int j = 0;
llist * list = new_llist ();
for ( i = 0; i < 100; i++ ) {
for ( j = 0; j < 100; j++ ) {
add_int_tail ( i+j, list );
}
}
printf("enter to continue and free memory...");
getchar();
destroy_list ( list );
printf("memory freed. enter to exit...");
getchar();
printf( "\n");
return 0;
}
【问题讨论】:
标签: memory malloc free memory-leaks