两个接口的 F# 显式接口方法答案

【问题标题】：F# Explicit Interface Method for Two Interfaces两个接口的 F# 显式接口方法
【发布时间】：2012-05-21 02:31:55
【问题描述】：

处理这种情况的正确方法是什么。我的 F# 类 DogTree 中有一个方法应该满足为两个接口实现 Bark() 方法的要求。

type ITree =
    interface
        abstract Bark : unit -> unit
        abstract Grow : unit -> unit
    end

type IDog =
    interface
        abstract Bark : unit -> unit
        abstract ChaseCar : unit -> unit
    end

type TreeDog = 
   // so the "and" syntax below doesn't work - what is the correct way to handle?
   interface IDog and ITree with
      member this.Bark() = printfn "Bark"

【问题讨论】：

标签： .net interface f# explicit-interface

【解决方案1】：

您可以委托给一个通用实现：

type TreeDog = 
  interface IDog with
    member this.Bark() = printfn "Bark" 
  interface ITree with
    member this.Bark() = (this :> IDog).Bark()

或者，更恰当地说：

type TreeDog = 
  member this.Bark() = printfn "Bark"
  interface IDog with
    member this.Bark() = this.Bark() 
  interface ITree with
    member this.Bark() = this.Bark()

（请注意，这在名为Bark 的类中定义了一个额外的方法，用作两个接口的实现。）

如果你在你的类中声明一个主构造函数，你可以使用它来代替：

type TreeDog() = // primary constructor
  let bark() = printfn "Bark" // this member is private
  interface IDog with
    member this.Bark() = bark()
  interface ITree with
    member this.Bark() = bark()

【讨论】：

【解决方案2】：

这是相当优雅的

type TreeDog() = 
  let bark() = printfn "Bark" 
  interface IDog with
    member this.Bark() = bark()
  interface ITree with
    member this.Bark() = bark()

【讨论】：