$_POST 在新编辑的选项卡中打开 [重复]

Question

            <form method="post" target="_blank" action="battle.php" onsubmit="window.open('battle.php','','width=700,height=500,toolbar=0,menubar=0,location=0,status=0,scrollbars=0,resizable=0,left=30,top=0');" >
                <input type="hidden" name="username" value="<?php echo $username; ?>"/>
                <input type="hidden" name="password" value="<?php echo $password; ?>"/>
                <input type="submit" value="OPEN TO BATTLE.php"/>
            </form>

^^工作但不是我想要的方式。

当单击提交按钮时，我试图让这个表单打开一个大小为'width=700,height=500,toolbar=0,menubar=0,location=0,status=0,scrollbars=0,resizable=0,left=30,top=0'的新窗口。

我想要它以便将 $_POST 数据传输到新网页

Answer 1

试试这个：

<form method="post" action="battle.php" onsubmit='window.open("battle.php/?width=700&height=500&toolbar=0&menubar=0&location=0&status=0&scrollbars=0&resizable=0&left=30&top=0","_blank");' >

Answer 2

<form method="post" onsubmit="window.open('http://www.google.com', '_blank', 'toolbar=0,location=0,menubar=0');" >
                <input type="hidden" name="username" value="<?php echo $username; ?>"/>
                <input type="hidden" name="password" value="<?php echo $password; ?>"/>
                <input onclick="" type="submit" value="OPEN TO BATTLE.php"/>
            </form>