洗牌的简单方法

Question

我正在寻找一种简单的方法来洗牌。我已经完成了套牌，有什么简单的方法来创建一个洗牌 52 张牌的函数？我不是在寻找复杂的洗牌方式，我更喜欢我可以轻松阅读的代码。我尝试将 rand() 放在 cout 部分，但它只是随机化了花色和面孔，我得到了错误的牌。

struct Card 
    {
        int value;
        char suit;
    };
Card cards[52];   //global variables

int main()
{
    int play;

    shuffleDeck();
    cout << endl<<endl;
    cout << "---------------------------" << endl;
    cout << "|Welcome to The Game Of 31| " << endl;
    cout << "---------------------------" << endl;
    cout << "Would you like to play? (1 for 'YES', 0 for 'NO'): ";
    cin >> play;
    if (play == 1) { shuffleDeck(); }
    else { cout << "See yaa!"; exit(0); }



}


void shuffleDeck() {
    for (int i = 0; i < 52; i++)
    {
        cards[i].value = i % 13; // 13 values
        if (cards[i].value == 0) {
            cards[i].value = 1;
        }
        else if (cards[i].value == 1) {
            cards[i].value = 2;
        }
        else if (cards[i].value == 2) {
            cards[i].value = 3;
        }
        else if (cards[i].value == 3) {
            cards[i].value = 4;
        }
        else if (cards[i].value == 4) {
            cards[i].value = 5;
        }
        else if (cards[i].value == 5) {
            cards[i].value = 6;
        }
        else if (cards[i].value == 6) {
            cards[i].value = 7;
        }
        else if (cards[i].value == 7) {
            cards[i].value = 8;
        }
        else if (cards[i].value == 8) {
            cards[i].value = 9;
        }
        else if (cards[i].value == 9) {
            cards[i].value = 10;
        }
        else if (cards[i].value == 10) {
            cards[i].value = 10;

        }
        else if (cards[i].value == 11) {
            cards[i].value = 10;
        }
        else if (cards[i].value == 12) {
            cards[i].value = 10;
        }


        cards[i].suit = i / 13;// 4 suits
        if (cards[i].suit == 0) {
            cards[i].suit = 'D';
        }
        else if (cards[i].suit == 1) {
            cards[i].suit = 'H';
        }
        else if (cards[i].suit == 2) {
            cards[i].suit = 'C';
        }
        else if (cards[i].suit == 3) {
            cards[i].suit = 'S';
        }
    }

    for (int count = 0; count < 52; count++) {
        int count2 = 0;
        cout << " | " << cards[count].value;
        cout << cards[count].suit << " | ";

        if (count == 13) { cout << endl; }
        else if (count == 26) { cout << endl; }
        else if (count == 39) { cout << endl; }
        else if (count == 52) { cout << endl; }
    }
}

编辑：

void shuffleDeck() {
    theDeck();
    std::random_device rd;
    std::mt19937 g(rd());

    std::shuffle(cards, cards + 52, g);

    for (int count = 0; count < 52; count++) {
        int count2 = 0;
        cout << " | " << cards[count].value;
        cout << cards[count].suit << " | ";

        if (count == 13) { cout << endl; }
        else if (count == 26) { cout << endl; }
        else if (count == 39) { cout << endl; }
        else if (count == 52) { cout << endl; }
    }

Answer 1

你可以shuffle这样的卡片：

std::random_device rd;
std::mt19937 g(rd());

std::shuffle(cards, cards + 52, g);

不要担心太多第 2 行。您可以将其视为一种确保洗牌的方法很好。