简单的 Python 随机数猜测器答案

【问题标题】：Simple Python Random Number Guesser简单的 Python 随机数猜测器
【发布时间】：2017-09-08 07:22:41
【问题描述】：

我刚刚写了一个猜测随机数的快速脚本。虽然脚本“恭喜你赢了等”的最后一行没有运行。同样在某些解释器中，它会给出错误“无法运行脚本”。

import random 
attempts = 0
secret_number = random.randint(1,100)
isCorrect = False
guess = int(input("Take a guess: ")) 

while secret_number != guess: 
    if guess < secret_number:
        print("Higher...")
        guess = int(input("Take a guess: "))
        attempts+= 1 
    elif guess > secret_number:
        print("Lower...")
        guess = int(input("Take a guess: "))
        attempts+= 1 
    else:
        print("\nYou guessed it! The number was " ,secret_number)

【问题讨论】：

如果初始guess正确，则循环条件立即为假，不执行循环。
else 行永远不会执行，因为 while 循环条件在正确猜测时得到验证并退出循环。您可以删除 else 并取消缩进该行，以便在它突破 while 后显示
将最后一行移出while循环

标签： python random numbers

【解决方案1】：

我对您的脚本做了一些修改。请注意，它的功能是由执行流调节的，不需要特殊的控制语句（例如continue、break）或显式干预来使其逻辑一致：

import random 


secret_number = random.randint(1, 100)
guess = None
attempts = 0

while secret_number != guess: 
    guess = int(input("Take a guess: ")) 
    attempts += 1

    if secret_number == guess:
        print("\nYou guessed it! The number was ", secret_number)
    elif guess < secret_number:
        print("Higher...")
    elif guess > secret_number:
        print("Lower...")

我变了：

isCorrect 变量。我删除了它，因为它没有使用过；
guess 变量的初始化方式。在while语句之前是None；
while 循环内的条件语句；
在 while 循环内从用户读取输入的顺序。

我建议您直观地了解脚本工作的原因。

我尝试运行它并收到以下输出：

None@vacuum:~$ python3.6 ./test.py
Take a guess: 70
Higher...
Take a guess: 80
Higher...
Take a guess: 90
Higher...
Take a guess: 95
Lower...
Take a guess: 94
Lower...
Take a guess: 93
Lower...
Take a guess: 92
Lower...
Take a guess: 91

You guessed it! The number was  91

【讨论】：

【解决方案2】：

您应该在 while 循环之外打印该行，因为当 secret_number == guess 时您的循环会中断。

while ...:
    if: 
        ... 
    elif: 
        ...

print "You guessed it! The number was {0}".format(secret_number)

【讨论】：