创建互斥图像幻灯片（同时显示两个图像，不能相同）

Question

感谢您提前提供帮助。这是最近其他人提出的类似问题（Random Switch Statement Improvements?），但那里提供的解决方案对我没有用。

如果您不想访问该页面，这就是问题所在。我有 2 个幻灯片图像，一个在另一个之上。我希望这些图像永远不会相同，无论是在页面加载时还是在幻灯片无限播放时。

我已经尝试添加

"ORDER BY rand() LIMIT 2"

这只会使幻灯片图像消失。

代码如下：

$getRugInfo = "SELECT f_name, l_name, city, zipcode, dfd.name as state_id, rug_types, profile_photo, profile_url, prt.rating  FROM rug_owners ps 
left join rug_states pst on dfd.state_id = ps.state_id left join rug_reviews 
prt on dfd.user_id = ps.user_id  WHERE promoted_rug = 1 ORDER BY ";  


$range_values = range(1,6);
shuffle($range_values);
$pickRug=array_pop($range_values);

 // I tried doing the code above, but it did not make the slideshow images mutually exclusive.  THe same two images would show up on occasion.  

$pickRug = mt_rand(1, 5);

switch($pickRug) {
case 1:
    $getSliderInfo .= "f_name";
    break;
case 2:
    $getSliderInfo .= "l_name";
     break;
case 3:
    $getSliderInfo .= "city";
    break;
case 4:
    $getSliderInfo .= "profile_photo";
    break;
case 5:
    $getSliderInfo .= "city DESC";
    break;
}

$sliderResult = mysql_query($getSliderInfo); // calls the slideshow

$link_address = $row["profile_url"];

那么第二张幻灯片图像（底部的图像）与上面相同

这里是创建幻灯片的 Jquery：

 <script>
    jQuery('#Slider').cycle({ 
    fx:     'fade', 
    speed: 3000
});
    jQuery('#Slider2').cycle({ 
    fx:     'fade', 
    speed: 3000
});
</script>

同样，这与上面提供的链接中其他人遇到的问题基本相同，只是提供的解决方案不起作用。`

Answer 1

尝试增加随机数的范围，调整switch语句如下：

$pickRug = mt_rand(1, 15);

switch($pickRug) {
    case 1:
    case 4:
    case 7:
        $getSliderInfo .= "f_name";
        break;
    case 2:
    case 5:
    case 8:
        $getSliderInfo .= "l_name";
         break;
    case 3:
    case 6:
    case 9:
        $getSliderInfo .= "city";
        break;
    case 10:
    case 12:
    case 14:
        $getSliderInfo .= "profile_photo";
        break;
    case 11:
    case 13:
    case 15:
        $getSliderInfo .= "city DESC";
        break;
}

这种混杂会给你带来更独特的结果。

希望对你有帮助！！