字母数字字符串中带有可选点的正则表达式

Question

我正在尝试编写一个与可能包含点的固定字母数字字符串匹配的正则表达式。
此正则表达式必须匹配除点之外的所有字符。 我需要在 Javascript search() 中使用它来比较两个字符串。 要查找的单词：30A10Z20

所有这些都是正确的匹配：

30A1.0Z2.0
30A.10Z20
3.0.A10.Z20
3.0.A.1.0.Z.2.0.

我已经写了这些，但没有成功：

^30A10Z20\\.{0,1}?$
^30A10Z20\\.?$
^30A10Z20(?=\\.)

非常感谢任何线索或帮助。

Answer 1

我不确定RegExp 是否是完成我认为您想做的事情的最佳方式（基于您的 cmets：尝试重新制定您的问题）。这个 sn-p 会是一个主意吗？

const findTerm = (word, searchTerm) => 
  word.replace(/[^a-z0-9]/gi, "") === searchTerm;

const aFewStrings = [
  `something 30A1.0Z2.0 etc`,
  `30A.10Z20 hithere`,
  `Hello 3.0.A10.Z20`,
  `The value 3.0.....A.1.0....Z.2.0. may be valid`,
  `As may be the value 3.0@@@A.1.0#&!'Z.2.0.`,
  `Bye 3.0.A.1.0.Z.2.0. ended`,
];

aFewStrings.forEach(s => {
  const words = s.split(" ").map( w => findTerm(w, "30A10Z20") ? `<b>${w}</b>` : w );
  console.log(words.join(" "));
});

如果您想要部分字符串（参见您的评论），您必须进行一些解析。比如：

const findTerm = (word, searchTerm) =>
  RegExp(`(${searchTerm})`, "i").test(word.replace(/[^a-z0-9]/gi, ""));

const toBold = (word, searchTerm) => {
  const word2Parse = [...word];
  const wordPreserved = word2Parse.slice(0);
  const len = searchTerm.length;
  let foundIndices = [];
  let i = 0;

  while (word2Parse.length) {
    const noDots = word2Parse.slice(1).filter(v => !/[^a-z0-9]/i.test(v));
    const next = searchTerm.length > 1 &&  noDots[0] === searchTerm[1];
    const found = searchTerm.length > 1 
        ? word2Parse[0] === searchTerm[0] && next
        : word2Parse[0] === searchTerm[0];
    
    searchTerm = found ? searchTerm.slice(1) : searchTerm;
    found && foundIndices.push(i);
    i += 1;
    word2Parse.shift();
  }


  wordPreserved[foundIndices[0]] = `<b>${wordPreserved[foundIndices[0]]}`;
  wordPreserved[foundIndices.slice(-1)] = `${
        wordPreserved[foundIndices.slice(-1)]}</b>`;
  return wordPreserved.join("");
}

const aFewStrings = [
  `something 30A1.0Z2.0 etc`,
  `30A.10Z20 hithere`,
  `Hello 3.0.A10.Z20`,
  `The value 3.0.....A.1.0....Z.2.0. may be valid`,
  `As may be the value 3.0@@@A.1.0#&!'Z.2.0.`,
  `Bye 3.0.A.1.0.Z.2.0. ended`,
  `3.0.A.1.0.Z.2.....0`,
];


const result = document.querySelector("#result");

let term = `30A1`;
result.appendChild(
  Object.assign(
    document.createElement("p"), {
      innerHTML: `[1 String, search '30A1']: ${
          (aFewStrings[3].split(" ")
            .map(w =>
                findTerm(w, term) ? toBold(w, term) : w)
            .join(" "))}`
    })
);

term = `notfound`;
result.appendChild(
  Object.assign(
    document.createElement("p"), {
      innerHTML: `[1 String, search 'notfound']: ${
          (aFewStrings[1].split(" ")
            .map(w =>
                findTerm(w, term) ? toBold(w, term) : w)
            .join(" "))}`
    })
);

term = `0Z20`;
aFewStrings.forEach(s => {
  const words = s.split(" ").map(w =>
    findTerm(w, term) ? toBold(w, term) : w);
  result.appendChild(
    Object.assign(
      document.createElement("div"), {
        innerHTML: words.join(" ")
      })
  );
});

body {
  margin: 2rem;
  font: normal 12px/15px verdana, arial;
}

b {
  color: red;
}

<div id="result"></div>