ArrayList <Word> 无法转换为 int

Question

这可能是一个简单的问题，我看到过类似的问题，但我看不出他们的回答如何适用于我的问题，所以我提前道歉，但我收到了这个错误：
不兼容的类型：ArrayList 无法转换为 int

这是一个作业，我不确定我做错了什么。

这是我的代码：

package com.example.android.miwok;

import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.widget.ListView;

import java.util.ArrayList;

public class NumbersActivity extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_numbers);

        // Create a list of words
        ArrayList<Word> words = new ArrayList<Word>();
        words.add(new Word("one", "lutti"));
        words.add(new Word("two", "otiiko"));
        words.add(new Word("three", "tolookosu"));
        words.add(new Word("four", "oyyisa"));
        words.add(new Word("five", "massokka"));
        words.add(new Word("six", "temmokka"));
        words.add(new Word("seven", "kenekaku"));
        words.add(new Word("eight", "kawinta"));
        words.add(new Word("nine", "wo’e"));
        words.add(new Word("ten", "na’aacha"));

        // Create an {@link WordAdapter}, whose data source is a list of {@link Word}s. The
        // adapter knows how to create list items for each item in the list.
        WordAdapter adapter = new WordAdapter(this, words);

        // Find the {@link ListView} object in the view hierarchy of the {@link Activity}.
        // There should be a {@link ListView} with the view ID called list, which is declared in the
        // activity_numbers.xml layout file.
        ListView listView = (ListView) findViewById(R.id.list);

        // Make the {@link ListView} use the {@link WordAdapter} we created above, so that the
        // {@link ListView} will display list items for each {@link Word} in the list.
        listView.setAdapter(adapter);
    }

我在这一行收到错误：

WordAdapter adapter = new WordAdapter(this, words);

这是我的适配器代码：

package com.example.android.miwok;

        import android.content.Context;
        import android.view.LayoutInflater;
        import android.view.View;
        import android.view.ViewGroup;
        import android.widget.ArrayAdapter;

        import java.util.ArrayList;

/**
 * Created by danle on 7/25/2016.
 */
public class WordAdapter extends ArrayAdapter<Word> {
    public WordAdapter(Context context, int resource) {
        super(context, resource);
    }

    public WordAdapter(NumbersActivity context, int resource, ArrayList<Word> words) {
        super(context, resource, words);
    }




    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        View listItemView = convertView;
        if (listItemView == null) {
            listItemView = LayoutInflater.from(getContext()).inflate(
                    R.layout.list_item, parent, false);
        }
        return listItemView;
    }
}

Answer 1

问题是你的第二个构造函数。 ArrayAdapter 没有超级构造函数，它只需要一个上下文和一个 ArrayList<Word>。所以那个 super 正在调用(Context, int) 并尝试将单词转换为整数资源。

public WordAdapter(NumbersActivity context, ArrayList<Word> words) {
    super(context, words);
}

你的构造函数应该是

public WordAdapter(NumbersActivity context, int resource, ArrayList<Word> words) {
    super(context, resource, words);
}

Answer 2

public WordAdapter(NumbersActivity context, ArrayList<Word> words) {
        super(context, words);
    }

尝试使用对象“words”设置资源ID。

使用以下构造函数：

ArrayAdapter(Context context, int resource, T[] objects)

See Also

Answer 3

你的构造函数

public WordAdapter(NumbersActivity context, ArrayList<Word> words) {
        super(context, words);
}

正在调用在 Super 类中没有直接匹配的 super(context, words);。所以它与ArrayAdapter(Context context, int resource) 匹配。因此分配错误并将ArrayList 分配给int 问题。您应该使用 Super 类中的以下构造函数

ArrayAdapter(Context context, int resource, T[] objects)

希望对你有帮助

编辑

所以你需要将上面提到的代码替换为

 public WordAdapter(NumbersActivity context, int resource, ArrayList<Word> words) {
        super(context, resource, words);
 }

然后这样称呼它：

WordAdapter adapter = new WordAdapter(this,<resource id for list item android.R.layout.xxx>, words);

Answer 4

只需将您的适配器更改为：

public class WordAdapter extends BaseAdapter {

    ArrayList<Word> items=new ArrayList();

    Context mContext;

    public WordAdapter(Context context,  ArrayList<Word> words) {
        items=words;
        mContext=context;
    }

    @Override
    public int getCount() {
        return items.size();
    }

    @Override
    public Object getItem(int position) {
        return items.get(position);
    }

    @Override
    public long getItemId(int position) {
        return 0;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        Word mWord=items.get(position);
        View listItemView = convertView;
        if (listItemView == null) {
            listItemView = LayoutInflater.from(mContext).inflate(
                    R.layout.list_item, parent, false);
        }
        return listItemView;
    }
}

Answer 5

花一整天时间找出我的错误，但你的文件 wordAdapter 中有你的错误：

应该是这样的：

public class WordAdapter extends ArrayAdapter<Word> {


    public WordAdapter(Activity context, ArrayList<Word> words) {
        // Here, we initialize the ArrayAdapter's internal storage for the context and the list.
        // the second argument is used when the ArrayAdapter is populating a single TextView.
        // Because this is a custom adapter for two TextViews and an ImageView, the adapter is not
        // going to use this second argument, so it can be any value. Here, we used 0.
        super(context, 0, words);
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        // Check if the existing view is being reused, otherwise inflate the view
        View listItemView = convertView;
        if(listItemView == null) {
            listItemView = LayoutInflater.from(getContext()).inflate(
                    R.layout.simple_list_item_3, parent, false);
        }

        // Get the {@link AndroidFlavor} object located at this position in the list
        Word currentWord = getItem(position);

        // Find the TextView in the list_item.xml layout with the ID version_name
        TextView mongolTextView = (TextView) listItemView.findViewById(R.id.mongol_text_view);
        // Get the version name from the current AndroidFlavor object and
        // set this text on the name TextView
        mongolTextView.setText(currentWord.getmMongolTranslation());

        // Find the TextView in the list_item.xml layout with the ID version_number
        TextView defaultTextView = (TextView) listItemView.findViewById(R.id.default_text_view);
        // Get the version number from the current AndroidFlavor object and
        // set this text on the number TextView
        defaultTextView.setText(currentWord.getmDefaultTranslation());


        // Return the whole list item layout (containing 2 TextViews and an ImageView)
        // so that it can be shown in the ListView
        return listItemView;
    }
}