是否可以通过引用来获取函数的名称？ [复制]

Question

我有以下代码：

function abcdef() { }

function test($callback) {
    // I need the function name string("abcdef") here?
}

test(abcdef);

是否可以在测试函数中获取函数名？ 那么匿名函数呢？

Answer 1

以前有人问过这个问题：How can I get the callee in PHP?

您可以通过debug_backtace 获取您需要的信息。这是一个非常干净的函数I have found：

<?php
/**
 * Gets the caller of the function where this function is called from
 * @param string what to return? (Leave empty to get all, or specify: "class", "function", "line", "class", etc.) - options see: http://php.net/manual/en/function.debug-backtrace.php
 */
function get_caller($what = NULL)
{
    $trace = debug_backtrace();
    $previousCall = $trace[2]; // 0 is this call, 1 is call in previous function, 2 is caller of that function

    if(isset($what)) {
        return $previousCall[$what];
    } else {
        return $previousCall;
    }   
}

你（可能）这样使用它：

<?php
function foo($full)
{
    if ($full) {
        return var_export(get_caller(), true);
    } else {
        return 'foo called from ' . get_caller('function') . PHP_EOL;
    }
}

function bar($full = false)
{
    return foo($full);
}

echo bar();
echo PHP_EOL;
echo bar(true);

返回：

foo called from bar

array (
  'file' => '/var/www/sentinel/caller.php',
  'line' => 31,
  'function' => 'bar',
  'args' =>
  array (
    0 => true,
  ),
)

Answer 2

你可以试试 function.name ：

function abcdef() { }

function test($callback) {
    alert($callback.name)
}

test(abcdef);