Java扫描程序中断等待输入[重复]

Question

如何在 Java 中中断等待输入？

        Scanner s = new Scanner() ;
        s.nextInt();
        //here break without input

我想创建一个 while 循环，您可以在其中输入 5 分钟的内容。 5分钟后循环应该被打破。但是当时间结束时，循环不会再次执行，但扫描仪仍在等待输入并进入。

我想退出等待输入，我不是说打破while循环。

Answer 1

如果我正确理解你的问题，这就是你想要的：

import java.util.Scanner;
import java.util.concurrent.FutureTask;
import java.util.concurrent.TimeUnit;
import java.util.concurrent.TimeoutException;

public class Testes {
    public static void main(String[] args) throws Exception {
        try {
            while (true) {
                System.out.println("Insert int here:");
                Scanner s = new Scanner(System.in);

                FutureTask<Integer> task = new FutureTask<>(() -> {
                    return s.nextInt();
                });

                Thread thread = new Thread(task);
                thread.setDaemon(true);
                thread.start();
                Integer nextInt = task.get(5, TimeUnit.MINUTES);

                System.out.println("Next int read: " + nextInt + "\n----------------");
            }
        } catch (TimeoutException interruptedException) {
            System.out.println("Too slow, i'm going home");
            System.exit(0);
        }
    }
}

Answer 2

试试这个

导入 java.util.Scanner;

导入 java.util.concurrent.*;

公共类扫描{

public static void main(String arg[]) throws Exception{
    Callable<Integer> k = new Callable<Integer>(){

        @Override
        public Integer call() throws Exception {
            System.out.println("Enter x :");
            return new Scanner(System.in).nextInt();
        }

    };
    Long start= System.currentTimeMillis();
    int x=0;
    ExecutorService l = Executors.newFixedThreadPool(1);  ; 
    Future<Integer> g;
    g= l.submit(k);
    while(System.currentTimeMillis()-start<10000&&!g.isDone()){

    }
    if(g.isDone()){
        x=g.get();
    }
    g.cancel(true);

    if(x==0){
        System.out.println("Shut Down as no value is enter after 10s"  );
    } else {
        System.out.println("Shut Down as X is entered "  + x );
    }
    //Continuation of your code here....
}

}