【发布时间】:2012-05-20 15:40:29
【问题描述】:
我试图创建一个 TFTP 服务器,但是当它接收到一个文件时,似乎并非所有文件都保存在服务器上(缺少一些字节)。该文件创建良好,大部分数据已写入,但由于文件不完整,它被归类为损坏且无法打开。有谁知道如何解决这个问题?
主类
WRQ WRQ = new WRQ();
ACK ACK = new ACK();
DatagramPacket outPacket;
BufferedOutputStream bufferedOutput = new BufferedOutputStream(new FileOutputStream(filename));
byte[] bytes;
byte[] fileOut;
outPacket = WRQ.firstPacket(packet);
socket.send(outPacket);
socket.receive(packet);
while (packet.getLength() == 516){
bytes = WRQ.doWRQ(packet);
bufferedOutput.write(bytes);
outPacket = ACK.doACK(packet);
socket.send(outPacket);
socket.receive(packet);
}
bytes = WRQ.doWRQ(packet);
bufferedOutput.write(bytes);
bufferedOutput.close();
outPacket = ACK.doACK(packet);
socket.send(outPacket);
WRQ 类
public class WRQ {
public DatagramPacket firstPacket(DatagramPacket packet) throws IOException{
ACK ACK = new ACK();
DatagramPacket ACKpacket = ACK.doACK(packet);
//takes ACK packet and sets block # as 0 to signal that this is the first packet in a WRQ
byte[] ACKcontents = new byte[3];
ACKcontents = ACKpacket.getData();
ACKcontents[2] = 0;
ACKcontents[3] = 0;
ACKpacket.setData(ACKcontents);
return ACKpacket;
}
public byte[] doWRQ(DatagramPacket packet){
int length = packet.getLength();
byte[] packetData = packet.getData();
byte[] data = new byte[length - 4];
data = Arrays.copyOfRange(packetData, 4, length - 4);
return data;
}
}
【问题讨论】:
-
你可以编辑你之前的问题。
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感谢您的帮助。下次我会记住这一点。你能帮我解答这个问题吗?
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问题可能出在您没有向我们展示的代码中。例如 WRQ.doWRQ() 方法。尝试记录客户端发送的字节,并写入服务器上的文件,并比较它们。
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问题在于接收到的最后一批数据。它没有写入文件。我会进一步调查,但在此期间的任何帮助都非常感谢。
标签: java fileoutputstream tftp bufferedoutputstream