【问题标题】:C++ Winapi, Popup window will open once but won't re-openC ++ Winapi,弹出窗口将打开一次但不会重新打开
【发布时间】:2015-10-14 19:16:21
【问题描述】:

我使用的是 Windows,Visual Studio 2015。我遇到的问题是我有一个可以打开子弹出窗口的按钮,第一次可以正常运行,但是一旦关闭弹出窗口并单击按钮再次它不会重新打开。

我有一个全局变量 hwnd2 因为目前我不知道如何在另一个函数中访问该变量,除非它是全局的。只是让你们知道你们就像“eww,全局变量”

可能有一些完全错误的东西,但搜索互联网不断让我走到这一步,没有人真正具体/深入。

#include "stdafx.h"
#include "Win32Project1.h"
#include <Windows.h>

#define IDB_CLICK_ME 200
HWND hwnd2;
LRESULT CALLBACK WndProc(HWND, UINT, WPARAM, LPARAM);
LRESULT CALLBACK WndProc2(HWND hwnd, UINT message, WPARAM wparam, LPARAM lparam);

int WINAPI WinMain (HINSTANCE hInstance, HINSTANCE hPrevInstance, PSTR szCmdLine , int iCmdShow)
{
    wchar_t wzAppName[] = L"GameLauncher";
    wchar_t wzAppName2[] = L"GameTest";
    MSG msg;
    HWND hwnd;
    WNDCLASS wndclass, wndclass2;
    wndclass.lpfnWndProc = WndProc;
    wndclass.cbClsExtra = 0;
    wndclass.cbWndExtra = 0;
    wndclass.hbrBackground = (HBRUSH)GetStockObject(WHITE_BRUSH);
    wndclass.hCursor = LoadCursor(NULL, IDC_ARROW);
    wndclass.hIcon = LoadIcon(NULL, IDI_APPLICATION);
    wndclass.hInstance = hInstance;
    wndclass.lpszClassName = wzAppName;
    wndclass.lpszMenuName = NULL;
    wndclass.style = CS_HREDRAW | CS_VREDRAW;

    wndclass2.lpfnWndProc = WndProc2;
    wndclass2.cbClsExtra = 0;
    wndclass2.cbWndExtra = 0;
    wndclass2.hbrBackground = (HBRUSH)GetStockObject(WHITE_BRUSH);
    wndclass2.hCursor = LoadCursor(NULL, IDC_ARROW);
    wndclass2.hIcon = LoadIcon(NULL, IDI_APPLICATION);
    wndclass2.hInstance = hInstance;
    wndclass2.lpszClassName = wzAppName2;
    wndclass2.lpszMenuName = NULL;
    wndclass2.style = CS_HREDRAW | CS_VREDRAW;


    RegisterClass(&wndclass);
    RegisterClass(&wndclass2);

    hwnd = CreateWindow(wzAppName, L"Tutorial", WS_OVERLAPPEDWINDOW, CW_USEDEFAULT, CW_USEDEFAULT, CW_USEDEFAULT, CW_USEDEFAULT, NULL, NULL, hInstance, NULL);

    hwnd2 = CreateWindow(wzAppName2, L"Options", WS_POPUPWINDOW | WS_CAPTION, 100, 100, 500, 300, hwnd, NULL, NULL, NULL);

    ShowWindow(hwnd, iCmdShow);
    UpdateWindow(hwnd);

    while (GetMessage(&msg, NULL, 0, 0))
    {
        TranslateMessage(&msg);
        DispatchMessage(&msg);
    }

}

LRESULT CALLBACK WndProc(HWND hwnd, UINT message, WPARAM wparam, LPARAM lparam)
{
    HDC hdc;
    PAINTSTRUCT ps;
    RECT rect;

    switch (message)
    {
        case WM_CREATE:
            CreateWindow(L"button", L"CLICK ME", WS_CHILD | WS_VISIBLE, 5, 5, 200, 25, hwnd, (HMENU) IDB_CLICK_ME, NULL, NULL);
            break;

        case WM_PAINT:
            hdc = BeginPaint(hwnd, &ps);
            GetClientRect(hwnd, &rect);
            DrawText(hdc, L"Hello", -1, &rect, DT_SINGLELINE | DT_CENTER | DT_VCENTER);
            EndPaint(hwnd, &ps);
            break;

        case WM_COMMAND:
            switch (LOWORD(wparam));
            {
                case IDB_CLICK_ME:
                    ShowWindow(hwnd2, 1);
                    UpdateWindow(hwnd2);
                    break;

            }

        break;

        case WM_DESTROY:
            PostQuitMessage(0);
            break;

        default:
            return DefWindowProc(hwnd, message, wparam, lparam);
    }

    return 0;
}

LRESULT CALLBACK WndProc2(HWND hwnd, UINT message, WPARAM wparam, LPARAM lparam)
{
    switch (message)
    {
        case WM_CREATE:
            break;

        case WM_DESTROY:
            return 0;

        default:
            return DefWindowProc(hwnd, message, wparam, lparam);
    }
    return 0;
}

【问题讨论】:

    标签: c++ winapi button popup


    【解决方案1】:

    当您关闭弹出窗口时,它不仅仅是隐藏的。它被摧毁了。如果您想要不同的行为,您可以处理 WM_CLOSEDefWindowProc 只需调用 DestroyWindow)。

    【讨论】:

    • 扩展这个答案:这是因为WM_CLOSE的默认行为,当您单击窗口的关闭按钮时发送,是销毁窗口。
    • @andlabs 有道理,有没有办法让它隐藏而不是被破坏? (更改默认行为)
    • CloseWindow() 最小化一个窗口(令人困惑)。你想要ShowWindow(hwnd2, SW_HIDE)。在WM_CLOSE 中执行此操作,并且不要在那里调用 DefWindowProc()
    • @andlabs,干杯和 hth。 - Alf 我要感谢你们两位花时间帮助我解决这个问题。我已经解决了,非常感谢所有的反馈。
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