【发布时间】:2016-04-07 01:42:41
【问题描述】:
我在 c++ 中有一个浮点数组,我想将它保存到一个二进制文件中(以节省空间),以便以后能够再次读取它。为此,我编写了以下代码来编写数组:
float *zbuffer = new float[viewport[3]*viewport[2]*4];
//.....
//.. populate array
//.....
ofstream zOut(string(outFile).append("_geom.txt", ios::out | ios::binary));
zOut.write(reinterpret_cast<char*>(zBuffer), sizeof(float)*viewport[3] * viewport[2] * 4);
zOut.close();
然后我立即重新打开文件以检查数据是否正确保存:
ifstream zIn(string(outFile).append("_geom.txt"), ios::in | ios::binary);
float *chBuffer = new float[viewport[3] * viewport[2] * 4];
zIn.read(reinterpret_cast<char*>(chBuffer), sizeof(float)*viewport[3] * viewport[2] * 4);
zIn.close();
但是,当我检查两个数组是否相等时,我得到的值截然不同:
for (int i = 0; i < viewport[3]; i++)
{
for (int j = 0; j < viewport[2]; j++)
{
int idx = 4 * (i*viewport[2] + j);
if ((zBuffer[idx] != chBuffer[idx]) || (zBuffer[idx + 1] != chBuffer[idx + 1]) || (zBuffer[idx + 2] != chBuffer[idx + 2])) {
cout << "1: " << zBuffer[idx] << " " << zBuffer[idx + 1] << " " << zBuffer[idx + 2] << endl;
cout << "2: " << chBuffer[idx] << " " << chBuffer[idx + 1] << " " << chBuffer[idx + 2] << endl;
}
}
}
我是否错误地读取或写入数据?我读取的数据的转换有什么问题吗?
【问题讨论】:
-
看起来不错。什么才算“大不相同”?