c ++无法从键盘输入tada

Question

我是编程新手，我想知道如何在课堂上从键盘输入数据。任何人？

#include <iostream>
#include <string>
using namespace std;

class Human{
private:
    string *name;
    int *age;
public:
    Human(string iname, int iage){
    name = new string;
    age = new int;

    *name = iname;
    *age = iage;
}
void display(){
    cout << "Hi I am " << *name << " and I am " << *age << " years old"  << endl;
}
~Human(){
delete name;
delete age;
cout << "Destructor!";
}
void input(string, int)
{
string name;
int age;
cout << "Name: "; cin >> name;
cout << "Age: "; cin >> age;
}
};

int main()
{

    Human *d1 = new Human(Human::input(?????????????????));
    d1->display();
    delete d1;
    return 0;
}  

编辑：

我明白我能做到这一点：

int main()
{

    Human *d1 = new Human("David",24);
    d1->display();
    return 0;
}

还有这个：

  int main()
{
    string name;
    int age;
    cout << "Name: "; cin >> name;
    cout << "Age: "; cin >> age;
    Human *d1 = new Human(name,age);
    d1->display();
    return 0;
}

但我想知道如何将键盘中的数据与输入功能一起输入。

Answer 1

Zygis 你需要阅读 C++ 基础教程。指针，*，是程序员可以使用的强大功能，但仅在需要时。在这种情况下，您不需要这样做。你什么时候需要它们？我认为你应该把它留到以后，并专注于我下面的例子。当你明白这一点后，你可以阅读互联网上的指针。

#include <iostream>
#include <string>
using namespace std;

class Human {
private:
    // data members of class
    string name;
    int age;
public:
    // constructor without arguments
    // useful for initializing the data members
    // by an input function
    Human() {
        name = ""; // empty string
        age = -1;  // "empty" age
    }

    // constructor with arguments
    // useful when you know the values
    // of your arguments
    Human(string arg_name, int arg_age) {
        name = arg_name;
        age = arg_age;
    }

    void display() {
        cout << "Hi I am " << name << " and I am " << age << " years old"
                << endl;
    }

    // the data members will go out of scope automatically
    // since we haven't used new anywhere
    ~Human() {
        cout << "Destructor, but the default one would be OK too!\n";
    }

    // prompt the user to giving values for name and age
    void input() {
        cout << "Please input name: ";
        cin >> name;
        cout << "Please input age: ";
        cin >> age;
    }
};

int main() {

    // Let the user initialize the human
    Human human_obj_i;
    human_obj_i.input();
    human_obj_i.display();

    cout << "Now I am going to auto-initialize a human\n";

    // Let the program itseld initialize the human
    Human human_obj("Samaras", 23);
    human_obj.display();

    return 0;
}

示例运行：

Please input name: Foo
Please input age: 4
Hi I am Foo and I am 4 years old
Now I am going to auto-initialize a human
Hi I am Samaras and I am 23 years old
Destructor, but the default one would be OK too!
Destructor, but the default one would be OK too!

希望对您有所帮助！ ;)