在 Javascript 中过滤日期

Question

我正在尝试过滤包含大于特定日期的日期（从字符串转换）的数组..

_this.downloadData.forEach(_d => _d.LogTime = _d.LogTime.toString());

console.log(_this.downloadData.filter(x=>new Date(x.LogTime) > new Date('3/11/2019 7:29:12 AM')));

但过滤器总是返回零个项目

.

数组如下所示：

[0 … 99]
0:
CPUStat:""
Connectivity:""
DiskStatus:""
HostName:"HOSTname"
LastRebootStatus:null
LogTime:"Mon Mar 11 2019 07:39:12 GMT+0530 (India Standard Time)"

__proto__:
Object

Answer 1

您的大部分问题都包括不符合 ISO 8601 的日期时间格式。因此，您需要清理日期。 LogTime.substring(4,23) + obj.LogTime.substring(28,33) 将从您的字符串中获取重要部分。然后你可以使用moment.js (https://momentjs.com)，这是 JavaScript 处理时间的必备。

你可以运行下面的代码，看看它是否有效

// Your example time array
let timeArray = [
  { LogTime:"Mon Mar 11 2019 07:39:12 GMT+0530 (India Standard Time)" },
  { LogTime:"Mon Mar 11 2019 08:39:12 GMT+0530 (India Standard Time)" },
  { LogTime:"Mon Mar 11 2019 09:39:12 GMT+0530 (India Standard Time)" },
  { LogTime:"Mon Mar 11 2019 10:39:12 GMT+0530 (India Standard Time)" }
 ],
 format = "MMM MM YYYY HH:mm:ssZ",
    shouldBeAfter = moment('Mar 11 2019 09:00:12+0530', format),
    result,
    filterDateGreaterThan = function (obj){
      let sDate,
          mDate;
      
      sDate = obj.LogTime.substring(4,23) + obj.LogTime.substring(28,33);
      mDate = moment(sDate, format);
      // console.log(mDate);
      return mDate.isAfter(shouldBeAfter);
    };
 result = timeArray.filter(filterDateGreaterThan);
 console.log(result);

<script src="https://momentjs.com/downloads/moment.min.js"></script>

不使用 Moment.js 时的代码

// Your example time array
let timeArray = [
  { LogTime:"Mon Mar 11 2019 07:39:12 GMT+0530 (India Standard Time)" },
  { LogTime:"Mon Mar 11 2019 08:39:12 GMT+0530 (India Standard Time)" },
  { LogTime:"Mon Mar 11 2019 09:39:12 GMT+0530 (India Standard Time)" },
  { LogTime:"Mon Mar 11 2019 10:39:12 GMT+0530 (India Standard Time)" }
 ],
    shouldBeAfter = new Date('Mar 11 2019 09:00:12+0530'),
    result,
    filterDateGreaterThan = function (obj){
      let sDate,
          date;
      
      sDate = obj.LogTime.substring(4,23) + obj.LogTime.substring(28,33);
      date = new Date(sDate);
      return date.valueOf() > shouldBeAfter.valueOf();
    };
 result = timeArray.filter(filterDateGreaterThan);
 console.log(result);

Answer 2

您应该能够通过在输入中添加时区来解决您的问题。如果您不提供时区，您的浏览器将使用您的本地时区。例如，我的时区是 PDT，所以我最终会看到：

Without Timezone in input:
input  : 3/11/2019 7:29:12 AM
output : Mon Mar 11 2019 07:29:12 GMT-0700 (Pacific Daylight Time)

With Timezone in input:
input  : Mon Mar 11 2019 07:39:12 GMT+0530 (India Standard Time)
output : Sun Mar 10 2019 19:09:12 GMT-0700 (Pacific Daylight Time)

请注意，使用输入中的时区，unix 时间戳与输出相匹配。

---

我个人使用Moment Timezone 处理这些情况。

Without Timezone in input:
input  : moment.tz("3/11/2019 7:29:12 AM", "Asia/Calcutta").toDate();
output : Mon Mar 11 2019 00:29:12 GMT-0700 (Pacific Daylight Time)

With Timezone in input:
input  : moment.tz("Mon Mar 11 2019 07:39:12 GMT+0530 (India Standard Time)", "Asia/Calcutta").toDate();
output : Mon Mar 11 2019 00:39:12 GMT-0700 (Pacific Daylight Time)