【问题标题】:Hibernate HQL select distinct from where order by queryHibernate HQL select 与 where order by query 不同
【发布时间】:2019-10-18 19:20:24
【问题描述】:

我正在更新一个项目以明确了解客户,以前假设客户是这样的,因为我们只有一个...

我的问题是在我的 HQL 查询中添加 where 子句。

我的出发点是这个查询:

  public static final String SELECT_DISTINCT_STORES =
        "select DISTINCT e.storeNum, e.city, e.state from BoEngagement e order by e.storeNum";

我想添加一个 where e.customer_fk = :customer_fk 子句,但每次添加 where 子句时,我都会收到各种 org.hibernate.hql.internal.ast.QuerySyntaxException 错误,除非我取出 distinct 关键字,但我不相信查询会给我我所期待的。

这行得通:

   "select e.storeNum, e.city, e.state from BoEngagement e WHERE e.customer_fk = :customer_fk";

而且,如果我要简化查询,那真的应该是

"select e from BoEngagement e WHERE e.customer_fk = :customer_fk";

但是,就像我说的那样,我不相信删除 distinct 关键字是我想要做的。

以下是我尝试过的一些事情:

   "select DISTINCT e.storeNum, e.city, e.state FROM BoEngagement e WHERE e.customer_fk = :customer_fk order by e.storeNum";

给出这个错误

[ERROR] 2019-10-18 15:10:03.449 [main] BsRetrieveDistinct - java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: FROM near line 1, column 94 [SELECT DISTINCT e.city, e.state from com.bh.radar.bo.BoEngagement e order by e.state, e.city FROM com.bh.radar.bo.BoEngagement e WHERE e.customer_fk = :customer_fk]
java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: FROM near line 1, column 94 [SELECT DISTINCT e.city, e.state from com.bh.radar.bo.BoEngagement e order by e.state, e.city FROM com.bh.radar.bo.BoEngagement e WHERE e.customer_fk = :customer_fk]

还有这个更复杂的版本

   "select DISTINCT e.storeNum, e.city, e.state FROM BoEngagement e in " +
        "(select g FROM BoEngagement g WHERE g.customer_fk = :customer_fk order by g.storeNum)";

给出这个错误

[ERROR] 2019-10-18 15:08:14.317 [main] BsRetrieveDistinct - java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: in near line 1, column 81 [select DISTINCT e.storeNum, e.city, e.state FROM com.bh.radar.bo.BoEngagement e in (select g FROM com.bh.radar.bo.BoEngagement g WHERE g.customer_fk = :customer_fk order by g.storeNum)]
java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: in near line 1, column 81 [select DISTINCT e.storeNum, e.city, e.state FROM com.bh.radar.bo.BoEngagement e in (select g FROM com.bh.radar.bo.BoEngagement g WHERE g.customer_fk = :customer_fk order by g.storeNum)]

显然我并不完全理解 HQL 和 distinct 关键字。我做错了什么?

编辑:

@JB Nizet 评论说,根据我发布的错误,他认为我没有运行我发布的查询。我绝对正在运行该查询。我的疑惑是为什么我写的 HQL 会在 SQL 中生成两个 FROM 子句。我在下面粘贴了一个屏幕截图,显示了相关代码和错误消息。

【问题讨论】:

  • 报错说明查询有2个from子句。所以我认为你实际上并没有执行你发布的查询,它只有一个。

标签: java postgresql hibernate hql


【解决方案1】:

也许这不是我最初问题的答案,但是在互联网上搜索了几天并在这里发布我的问题并没有发现任何可以从我尝试过的各种 JPQL 字符串中生成理智的 PostgreSQL 查询的东西,所以我偶然发现了这个博文:The Many Faces of DISTINCT in PostgreSQL

从那里开始研究 EntityManager.createNativeQuery 方法,并提出了这个有效的 PostgreSQL 查询:

  public static final String SELECT_DISTINCT_STORES =
         "SELECT DISTINCT ON(storeNum, city, state) * FROM radar2.engagement WHERE customer_fk = :customer_fk ORDER BY storeNum asc, city, state";

我就是这样使用它的:

    results = em.createNativeQuery(SELECT_DISTINCT_CITY_STATES, BoEngagement.class)
                .setParameter("customer_fk", customer_fk)
                .getResultList();

现在,这个解决方案是特定于 PostgreSQL 的,但那是我现在使用的数据库,并且在不确定的未来使用。

【讨论】:

    猜你喜欢
    • 1970-01-01
    • 2019-03-15
    • 1970-01-01
    • 1970-01-01
    • 1970-01-01
    • 1970-01-01
    • 2014-10-03
    • 1970-01-01
    • 2012-02-25
    相关资源
    最近更新 更多