用瓦片洗牌向量数组

Question

我正在做一个学校项目。这是一个瓷砖移动游戏，我将屏幕上的瓷砖从瓷砖矢量数组中取出。

我正在尝试打乱瓷砖并将它们放入另一个名为 shuffledTiles 的矢量数组中，然后将它们显示在屏幕上，但我编写的代码仅适用于一个瓷砖。任何人都可以帮助我在错误的方式上做了什么。我是初级程序员。

这是我用来洗牌的代码：

void Game::ShuffleTiles()
{
    /* THIS FUNCTION IS TO CHOOSE A RANDOM TILE FROM THE TILES VECTOR STORAGE, TAKE ITS POSITION AND PUT IT INTO A NEW ARRAY CALLED SHUFFLED TILES, SET ITS POSITION TO THE 
    POSITION SAVED INTO A TEMPORARY VECTOR2F variable */

    // take items from 0 to 15 ->> 16 items
    for (int i = 0; i < this->tiles.size(); i++)
    {
        // setting the random seed by time to make sure different random number is given every time 
        srand(unsigned(time(NULL)));

        // Vector2f variable for storing the position of the random selected tile
        sf::Vector2f randTilePosXY;

        // integer for the random number between 0 and 16
        int randomNumber = rand() % this->tiles.size();

        // console out to see which random number is selected
        std::cout << "Random Number: " << randomNumber << std::endl;

        // taking the randomly selected tile's position and saving it into the Vector2f variable
        randTilePosXY == this->tiles[randomNumber].getPosition();

        //Showing the random tile's X and Y positions
        std::cout << "Random Number X and Y: " << std::stringstream(randTilePosXY) << std::endl;
        // putting the randomly selected tile to the end of the new shuffledTiles vector array
        this->shuffledTiles.push_back(this->tiles[randomNumber]);

        // setting the position of item in the shuffledTiles vector storage under the index number
        this->shuffledTiles[i].setPosition(sf::Vector2f(randTilePosXY));


    }

我想用这段代码向他们展示：

for (auto& s : this->shuffledTiles)
    {
        this->window->draw(s);
        this->window->draw(emptyTile);
    }

emptyTile 是右下角的图块，我不想更改它的位置，因为没有必要。

感谢您的帮助。

塔马斯

Answer 1

我认为你认为你的代码做了一件事，而实际上它并没有像你认为的那样做。你所做的基本上是：

// Step 1. Pick a tile from the existing set of tiles randomly.
int randomNumber = rand() % this->tiles.size();

// Step 2. Remember the randomly chosen tile's position
randTilePosXY == this->tiles[randomNumber].getPosition();

// Step 3. Copy the randomly chosen tile into a separate vector.
// THIS WILL COPY ALL INFORMATION OF THE TILE, INCLUDING ITS POSITION!
this->shuffledTiles.push_back(this->tiles[randomNumber]);

// Step 4. Copy AGAIN the POSITION INFORMATION.
// THIS STEP IS COMPLETELY USELESS AS YOU JUST OVERWRITE THE POSITION WITH THE SAME POSITION.
this->shuffledTiles[i].setPosition(sf::Vector2f(randTilePosXY));

您的“洗牌”矢量只不过是完全相同的信息，只是顺序不同。以下是正在发生的事情：

vector<tile> tiles = {{0, 0}, {1, 1}, {2, 2}}; // Three tiles at different positions.

// "Shuffle" the tiles...

shuffledTiles = {{1, 1}, {2, 2}, {0, 0}};

你在这里洗了什么？无论您打印tiles 还是shuffledTiles，您能看到结果将如何完全相同？

编辑：顺便说一句，这行代码：srand(unsigned(time(NULL))); 在整个程序中应该只出现一次。把它放在main 函数的顶部。随机生成器只需播种一次。

Answer 2

This is how it looks like now.

我完全不明白你在解释什么。

而这也是我想要达到的，只是每次加载程序的时候位置都不一样。

Shuffled Tiles