根据c#中的两个出生日期，占星术星星之间的兼容性#答案

【问题标题】：compatibility between astrological stars according to two dates of birth in c#根据c#中的两个出生日期，占星术星星之间的兼容性#
【发布时间】：2014-03-24 07:37:29
【问题描述】：

我有一个关于我的小项目的问题，该项目基于通过检查两个出生日期来检查两个占星术恒星之间的兼容性（例如：第一人的出生日期（1-19（第一个数字代表月份和第二个数字代表日期））然后相应地输入第二个人的出生日期。当我输入两个出生日期时，我的代码正常工作意味着它根据输入的出生日期告诉月份，日期和占星术。但是当我试图查找两个特定星之间的兼容性只计算 if else 语句中的第一个结果，如果结果是第一个 if else 控制结构未找到它不是跳转到下一个 else if 语句，而是直接跳转到最后一个 else 语句.. 我是第一次在这里发布问题请帮助我..如果有人可以这里是我的代码示例！！！

DateTime date = Convert.ToDateTime(Console.ReadLine());
            Console.WriteLine("Month:" + date.Month);
            Console.WriteLine("Day:" + date.Day);
            month = date.Month;
            day = date.Day;
            month1=date1.Month;
            day1=date1.Day;
string[] stringArr = { "January", "February", "march", "April", "may", "June", "July", "august", "September", "October", "November", "December"};
switch (month)
        {
            case 1:
                if (day <= 19)
                    return "Capricorn";
                else
                    return "Aquarius";

            case 2:
                if (day <= 18)
                    return "Aquarius";
                else
                    return "Pisces";
            case 3:
                if (day <= 20)
                    return "Pisces";
                else
                    return "Aries";
            case 4:
                if (day <= 19)
                    return "Aries";
                else
                    return "Taurus";
            case 5:
                if (day <= 20)
                    return "Taurus";
                else
                    return "Gemini";
            case 6:
                if (day <= 20)
                    return "Gemini";
                else
                    return "Cancer";
            case 7:
                if (day <= 22)
                    return "Cancer";
                else
                    return "Leo";
            case 8:
                if (day <= 22)
                    return "Leo";
                else
                    return "Virgo";
            case 9:
                if (day <= 22)
                    return "Virgo";
                else
                    return "Libra";
            case 10:
                if (day <= 22)
                    return "Libra";
                else
                    return "Scorpio";
            case 11:
                if (day <= 21)
                    return "Scorpio";
                else
                    return "Sagittarius";
            case 12:
                if (day <= 21)
                    return "Sagittarius";
                else
                    return "Capricorn";

        return "";
       }

同时计算另一个人的出生日期。问题来了。。

if (ob.month.Equals(1) && ob1.month1.Equals(1))
{

    if (ob.day <= 19 && ob1.day1 <= 19)
    {
        Console.WriteLine("Compatibility of Capricon with Capricon");
    }
    // else if (ob.day <= 19 && ob1.day1 > 19)
    else
    {
        Console.WriteLine("Compatibility of Capricon with Aquarius");
    }
}

else if (ob.month.Equals(1) && ob.month1.Equals(2))
{

    if (ob.day <= 19 && ob1.day1 <= 18)
    {
        Console.WriteLine("Compatibility of Capricon with Aquarius");
    }
    //else if (ob.day <= 19 && ob1.day1 > 18)
    else
    {
        Console.WriteLine("Compatibility of Capricon with Pisces");
    }
}
else if (ob.month.Equals(1) && ob.month1.Equals(3))
{
    if (ob.day <= 19 && ob.day1 <= 20)
    {
        Console.WriteLine("Compatibility of Capricon with Pisces");
    }
    else
    {
        Console.WriteLine("Compatibility of Capricon with Aries");
    }
}
else
    {consle.writeLine("invalid");
    }

此代码仅对第一个 if else 语句做出响应，而不是对其他 if else.. 请帮助我..我应该如何解决这个问题！！！

【问题讨论】：

你花了这么多精力写这个问题:)

标签： c#

【解决方案1】：

你让它变得非常困难。让它更简单。

class Program
{
    enum ZodiacSign
    {
        Aries, // March 21 - April 20
        Taurus, // April 21 - May 21
        Gemini, // May 22 - June 21
        Cancer, // June 22 - July 22
        Leo, // July 23 -August 21
        Virgo, // August 22 - September 23
        Libra, // September 24 - October 23
        Scorpio, // October 24 - November 22
        Sagittarius, // November 23 - December 22
        Capricorn, // December 23 - January 20
        Aquarius, // January 21 - February 19
        Pisces // February 20- March 20
    }

    static ZodiacSign BirthdayToZodiacSign(DateTime birthday)
    {
        var periodEndList = new[] {
            new { PeriodEnd = new DateTime(birthday.Year, 1, 20), ZodiacSign = ZodiacSign.Capricorn },
            new { PeriodEnd = new DateTime(birthday.Year, 2, 19), ZodiacSign = ZodiacSign.Aquarius },
            new { PeriodEnd = new DateTime(birthday.Year, 3, 20), ZodiacSign = ZodiacSign.Pisces },
            new { PeriodEnd = new DateTime(birthday.Year, 4, 20), ZodiacSign = ZodiacSign.Aries },
            new { PeriodEnd = new DateTime(birthday.Year, 5, 21), ZodiacSign = ZodiacSign.Taurus },
            new { PeriodEnd = new DateTime(birthday.Year, 6, 21), ZodiacSign = ZodiacSign.Gemini },
            new { PeriodEnd = new DateTime(birthday.Year, 7, 22), ZodiacSign = ZodiacSign.Cancer },
            new { PeriodEnd = new DateTime(birthday.Year, 8, 21), ZodiacSign = ZodiacSign.Leo },
            new { PeriodEnd = new DateTime(birthday.Year, 9, 23), ZodiacSign = ZodiacSign.Virgo },
            new { PeriodEnd = new DateTime(birthday.Year, 10, 23), ZodiacSign = ZodiacSign.Libra },
            new { PeriodEnd = new DateTime(birthday.Year, 11, 22), ZodiacSign = ZodiacSign.Scorpio },
            new { PeriodEnd = new DateTime(birthday.Year, 12, 22), ZodiacSign = ZodiacSign.Sagittarius }
        };

        foreach (var periodEnd in periodEndList)
            if (birthday <= periodEnd.PeriodEnd)
                return periodEnd.ZodiacSign;
        return ZodiacSign.Capricorn;
    }

    static string GenerateCompatibilityString(DateTime birthday1, DateTime birthday2)
    {
        return string.Format("Compatibility of {0} with {1}", BirthdayToZodiacSign(birthday1), BirthdayToZodiacSign(birthday2));
    }

    static void Main(string[] args)
    {
        Console.WriteLine(GenerateCompatibilityString(new DateTime(2014, 1, 1), new DateTime(2014, 6, 7)));
    }
}

【讨论】：

【解决方案2】：

我还没有完全阅读您的代码（因为它似乎不完整，例如 ob 是什么），但这里有一个一般性评论：

如果你有一个if else-if 构造，那么只会执行一个分支。例如。在以下示例中，将只执行一个代码块（对应于第一个条件评估为true 的代码块）：

if (condition1)
{}
else if (condition2)
{}
else if (condition3)
{}
else
{}

如果您有多个条件可以评估为true，那么您应该使用多个if 语句来代替：

if (condition1)
{}
if (condition2)
{}
if (condition3)
{}
// if you need an "else" part:
if (!condition1 && !condition2 && !condition3)
{}

【讨论】：

【解决方案3】：

这是一个解决这个问题的简单类：

public class Signs
{
  static List<string> SignList = new List<string>() {
    "Capricorn", "Aquarius", "Pisces", "Aries", "Taurus", "Gemini", "Cancer", "Leo", "Virgo", "Libra", "Scorpio", "Sagittarius", "Capricorn", "Not Found" };

  static List<int> StartDates = new List<int>() {
    // month * 100 + day of month
     120, 219, 320, 420, 521, 621, 722, 821, 923, 1023, 1122, 1222, 1232, 9999 // edge marker
  };

  static public string Sign(DateTime inDate)
  {
    return SignList[StartDates.TakeWhile(d => (inDate.Month*100)+inDate.Day > d).Count()];
  }
}

这里有另一个版本可能更清楚https://stackoverflow.com/a/23183480/215752

【讨论】：