JS：字符串的正则表达式

Question

我有 js 和一个不同的字符串，像这样：

Tue Aug 11 2015 between  4:00 PM and  5:00 PM

字词between 和and 未更改 但有时我可以得到这个字符串，单词之间有不同数量的空格

Tue Aug 11 2015 between   4:00 PM and   5:00 PM  (3 spaces)

或

Tue Aug 11 2015 between 4:00 PM and 5:00 PM (1 spaces)

是否可以为这个字符串创建一个正则表达式？

  string re1="((?:Monday|Tuesday|Wednesday|Thursday|Friday|Saturday|Sunday|Tues|Thur|Thurs|Sun|Mon|Tue|Wed|Thu|Fri|Sat))";  // Day Of Week 1
  string re2="(\\s+)";  // White Space 1
  string re3="((?:Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|Jun(?:e)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|Sept|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?))"; // Month 1
  string re4="(\\s+)";  // White Space 2
  string re5="((?:(?:[0-2]?\\d{1})|(?:[3][01]{1})))(?![\\d])";  // Day 1
  string re6="(\\s+)";  // White Space 3
  string re7="((?:(?:[1]{1}\\d{1}\\d{1}\\d{1})|(?:[2]{1}\\d{3})))(?![\\d])";    // Year 1
  string re8="(\\s+)";  // White Space 4
  string re9="(\"between\")";   // Double Quote String 1
  string re10="(\\s+)"; // White Space 5
  string re11="((?:(?:[0-1][0-9])|(?:[2][0-3])|(?:[0-9])):(?:[0-5][0-9])(?::[0-5][0-9])?(?:\\s?(?:am|AM|pm|PM))?)"; // HourMinuteSec 1
  string re12="(\\s+)"; // White Space 6
  string re13="(\"and\")";  // Double Quote String 2
  string re14="(\\s+)"; // White Space 7
  string re15="((?:(?:[0-1][0-9])|(?:[2][0-3])|(?:[0-9])):(?:[0-5][0-9])(?::[0-5][0-9])?(?:\\s?(?:am|AM|pm|PM))?)"; // HourMinuteSec 2

如何简化这一行的正则表达式？

Answer 1

这是我重复使用您的代码的尝试：

var re1="((?:Monday|Tuesday|Wednesday|Thursday|Friday|Saturday|Sunday|Tues|Thur|Thurs|Sun|Mon|Tue|Wed|Thu|Fri|Sat))";  // Day Of Week 1
var re2="\\s+";  // White Space 1
var re3="((?:Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|Jun(?:e)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|Sept|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?))"; // Month 1
var re5="((?:(?:[0-2]?\\d)|(?:3[01])))(?!\\d)";  // Day 1
var re7="(\\b(?:1\\d{3}|2\\d{3})\\b)";    // Year 1
var re11="((?:[0-1][0-9]|2[0-3]|[0-9]):[0-5][0-9](?::[0-5][0-9])?(?:\\s*(?:am|AM|pm|PM))?)"; // HourMinuteSec 
var reDay = "\\b((?:0?\\d|[12]\\d|3[01]))\\b";

var s = "Tue Aug 11 2015 between  4:00 PM and  5:00 PM";
var rx = RegExp(re1 + re2 + re3 + re2 + reDay + re2 + re7 + re2 + "between" + re2 + re11 + re2 + "and" + re2 + re11, 'i');
if ((m = rx.exec(s)) !== null) {
  document.write("Day of week: " + m[1] + "<br/>");
  document.write("Month: " + m[2] + "<br/>");
  document.write("Day: " + m[3] + "<br/>");
  document.write("Year: " + m[4] + "<br/>");
  document.write("From: " + m[5] + "<br/>");
  document.write("Till: " + m[6]);
  
}

请注意，我没有捕获空格（删除括号），添加了一个 reDay 几天，它只使用 \b\d{1,2}\b 捕获两个数字作为一个完整的单词，并且我已经找出了一些正则表达式（删除了不必要的括号）并通过将\s? 更改为\s* 来修复时间正则表达式。看起来这是主要问题，因为? 代表0 或1 次出现，而* 表示0 次或多次出现。

Answer 2

试试这个：

string.replace(/\s+/g,' ').trim();

它会删除所有多余的空间，每次只保留 1 个空间。 所以如果你有 3 个空格，就像你说的那样，它会将它转换为 1 个空格